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6*6*5*4*3*2*1/ (3! * 2!)zaarathelab wrote:How many numbers greater than 1000000 can be formed by using the digits 1, 2, 0, 2, 4, 2, 4?
a) 420
b) 360
c) 120
d) 600
e) 900
My way
[spoiler]Let's say the 7 digits represent 7 boxes. The first box can be filled in 6 ways (0 can't be there)
The second box in 6 ways
The third in 5 ways......so on. therefore - 6*6*5*4*3*2*1
But there are two 4s and three 2s
Therefore,
6*6*5*4*3*2*1/ (3! * 2!)
= 900
But the answer is B (360). In the above method, where am i going wrong?[/spoiler]
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