permutations

What is the OA? I think the answer I am getting is quite large to be correct.

my bad guys, i actually did not read the problem to the end and so got wrong answer. now it is corrected
2-men,4-women
3-men,3-women

8C2*5C4+8C3*5C3=28*5+56*10=140+560=700- is the number of committee that can be formed without restriction that two men refuse to sit together, now we calculate the number if commttee with exactly two men ( that refuse to sit both) and substract from 700

two men can be picked up the only way-1
4 women from 5 -5 outcomes
so 1 st with 2 men and 4 women 1*5=5 outcomes

now 3 men, two already given, the last - any from 6 left -6 ways
3 women from 5-10 outcomes, and total 1*6*10=60

together 5+60=65, and final result 700-65=635,-target answer

OA : 635

I got 360?? OA??

2 types of combinations:
3 Men , 3 Women
-Women can be chosen in 5C3 ways
-Men: since 2 men dont want to be together,lets make them one group.So we need to chose one of those 2 men.So 2C1
And need to choose 2 more men from remaining 6 men.So 6C2
So, 2C1 * 6C2* 5C3=300

2 Men, 4 Women
Women:5C4
Men:Again need to chose only one of the 2 men who dont want to be together,2C1
And choose one out of remaining 6,6C1
So,2C1+6C1*5C4=60

Total =300+60=360

chaitanyareddy wrote:Hi Experts,
Could you please give an explained solution to the following question.

A committee of 6 is chosen from 8 men and 5 women so as to contain at least 2
men and 3 women. How many different committees could be formed if two of the
men refuse to serve together?

Hmm.....this one involves very large numbers. I am not sure if this is a good GMAT problem. Whats the source?

answer is definately 635

to solve we can find total no of ways to find we can do the selection without any restictions as done by clock 60

then we can subtract the number of ways in which the two persons will come together ....which will come 65
hence subtacrt and answer is 635..

i hope this hint would help u guys reach the correct answer