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by goelmohit2002 » Sun Aug 16, 2009 11:08 am
In a certain test, a student must answer 8 out of 10 questions. How many choices are there if atleast 4 of the first 5 questions must be answered ?

OA = after some discussion.
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by prindaroy » Sun Aug 16, 2009 1:39 pm
5c3 * 5c5 + 5c4*5c4 = 10 + 25 = 35
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by tohellandback » Sun Aug 16, 2009 6:15 pm
5C3 + 5C4 *5C4=35
The powers of two are bloody impolite!!
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by goelmohit2002 » Sun Aug 16, 2009 6:51 pm
Thanks Guys. Answer is 35.
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by imhimanshu » Mon Aug 17, 2009 6:42 am
can anyone provide a detailed explanation..?I didnt get that.
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by tohellandback » Mon Aug 17, 2009 6:25 pm
imhimanshu wrote:can anyone provide a detailed explanation..?I didnt get that.
atleast 4 of the first 5 must be answered.
so one can either 4 of the first 5 and 4 of the second 5.
OR, one can answer 5 of the first five and 3 of the rest.
The powers of two are bloody impolite!!
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