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Permutation Question

Expert replies
by psburn » Fri Oct 10, 2008 12:54 am
In how many ways can a lawn tennis mixed double be made from seven married couples if no husband and wife play in the same set ?
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Source: — Problem Solving |

The answer is

by v_shiv » Fri Oct 10, 2008 7:13 am
7 males and 7 females. for each male, there can be 6 possible partners. 7*6 = 42. So, the answer is 42
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Re: The answer is

by dally_gmat » Fri Oct 10, 2008 1:36 pm
What is OA?
v_shiv wrote:7 males and 7 females. for each male, there can be 6 possible partners. 7*6 = 42. So, the answer is 42
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Re: The answer is

by dally_gmat » Fri Oct 10, 2008 1:54 pm
I may be wrong ..but heres what I think :

Total no of ways of selecting two teams for mixed double (2 Men. 2 Women):

2 M = 7*6
2G : 7*6

Total no of ways : 42*42 -----(A)

No of ways so that couple always play together = no of ways selecting 2 couples from 7 = 7*6 = 42------(B)

No of ways so that couple dont play together in a set = A-B = 42*42-42
= 42*41


dally_gmat wrote:What is OA?
v_shiv wrote:7 males and 7 females. for each male, there can be 6 possible partners. 7*6 = 42. So, the answer is 42
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by gmataug08 » Sun Oct 12, 2008 7:39 am
total available pairs = 7 * 6 = 42 pairs

total doubles combination possible = each of 42 pairs playing with any of the other 41 pairs

hence, 42*41 should be the answer.

what is OA?
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