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Permutation/Combination questions...

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by sibbineni » Sat Feb 02, 2008 1:23 pm
could you please post choices
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by sibbineni » Sat Feb 02, 2008 2:01 pm
let us consider the 2 girls are together then

GG BGBGBBB
GG GBGBBBB

which gives 2*8*5!*2!=3840.

now the 5 boys and 4 girls can be arranged in

BGBGBGBGB
GBGBGBGBB

2*5!*4!=5760

there fore no two girls sit together is 5760-3840=1920 ways
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by cris » Sat Feb 02, 2008 2:26 pm
1440 x 6 = 8640 ways
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by TkNeo » Sat Feb 02, 2008 3:07 pm
sibbineni wrote: =1920 ways
Incorrect.

cris wrote: 1440 x 6 = 8640 ways
Incorrect.
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by cris » Sat Feb 02, 2008 3:19 pm
true. 17,280?
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by Stuart@KaplanGMAT » Sat Feb 02, 2008 6:04 pm
Where is this question from?

Also, would you please post the actual question (the one you posted is too ambiguous, we need the original language to solve) and the answer choices?

Based on what you posted, there's no way that this would be an actual GMAT question - there are too many ways in which it can be interpreted.
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by TkNeo » Sat Feb 02, 2008 6:05 pm
cris wrote:true. 17,280?
Incorrect :)

Keep trying !
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by TkNeo » Sat Feb 02, 2008 6:11 pm
Stuart Kovinsky wrote:Where is this question from?

Also, would you please post the actual question (the one you posted is too ambiguous, we need the original language to solve) and the answer choices?

Based on what you posted, there's no way that this would be an actual GMAT question - there are too many ways in which it can be interpreted.

5 boys and 4 girls have to stand in a line so that no two girls are next to each other. How many distinct arrangements are possible. ?

Lets give each boy and girl a name just to make it more clear

B1 B2 B3 B4 B5 - boys
G1 G2 G3 G4 - girls

I don't have the 5 answer choices. If you don't want to solve the question without the answer choices that is ok !
Last edited by TkNeo on Sun Feb 03, 2008 6:57 am, edited 1 time in total.
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by sibbineni » Sat Feb 02, 2008 7:06 pm
Answer is 7680...
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by cris » Sun Feb 03, 2008 3:16 am
mmm I still think it has to be 17,280. I dont think that there is another way in which they can be seated with out being 2 girls together...

BGBGBGBGB
BBGBGBGBG
GBGBGBGBB
GBBGBGBGB
GBGBBGBGB
GBGBGBBGB

Update
---------------------------------------
I found 3 oher ways:

BGBBGBGBG
BGBGBBGBG
BGBGBGBBG

25,920 :D
Last edited by cris on Sun Feb 03, 2008 4:47 am, edited 1 time in total.
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by gabriel » Sun Feb 03, 2008 4:35 am
Well, not entirely sure but how about 6c4*5!*4!= 43,200 .. If it is right I will give my explanation for it.

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by gabriel » Sun Feb 03, 2008 4:41 am
cris wrote:mmm I still think it has to be 17,280. I dont think that there is another way in which they can be seated with out being 2 girls together...

BGBGBGBGB
BBGBGBGBG
GBGBGBGBB
GBBGBGBGB
GBGBBGBGB
GBGBGBBGB
You are missing out on many more possibilities like BGBGBBGBG or BGBGBGBBG or GBBGBGBBG or GBGBBGBBG .. there is a specific way to solve such questions, will write down those steps once my answer is confirmed.

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by cris » Sun Feb 03, 2008 4:53 am
Yep, Gabriel you are right, I have several more ways missing.

There has to be an easiest way than figuring out all the ways...this will def. take me more than 2 minutes...

I am sure you got the correct answer gabriel, you master these combination and permutations questions :)
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I think my answer is right just check and let me know

by senthil » Sun Feb 03, 2008 6:54 am
Hi , I feel the answer should be 43200 distinct ways!. if my answer is correct I will explain you the procedure ! This is just one of the normal question in Perm and Combi.


Thanks
Senthil L
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