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Source: — Problem Solving |

by niksworth » Sat Sep 04, 2010 11:56 pm
The required number of ways = Total possible groups of 3 - No. of groups of 3 without a senior partner. = A - B
A = 10C3 = 120
B = 6C3 = 20

Therefore the required no of groups of 3 with at least 1 senior partner = 120-20 = 100.
scio me nihil scire
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