Live GMAT classes with Target Test Prep start Nov 21 and Nov 22. First class free.

See classes
Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

Newsweek Readers’ Choice Awards 2026 winner: Target Test Prep, #1 Test Prep

Target Test Prep was voted #1 Best Test Prep in the 2026 Newsweek Readers’ Choice™ Awards.

★★★★★5.0563 reviews
GMATLiveTeachStarts Nov 22
Josh Braslow, Target Test Prep GMAT expert
LIVE ONLINE CLASSES

Get Ready for GMAT Test Day Faster with Live Online Classes

with Josh Braslow, 20+ years in test prep

Nov 22 · Josh Braslow
Sun · 9:30 AM to 12:30 PM ET
Included
40 hours of live online classes + 6 months of TTP OnDemand
  • Attend the first class for free
  • Every class is recorded, so you never fall behind
View classes & enroll
Limited seats availableTarget Test Prep
EALiveTeachOnDemandStart anytime
EXECUTIVE ASSESSMENT

Target Test Prep EA OnDemand

Self-paced EA prep. Study on your schedule.

EXECUTIVE ASSESSMENT

with

165+ EA score guarantee
$05-day trial no automatic billing
Schedule
Included
40 hours of live online classes plus six months of access to the complete TTP EA OnDemand course.
  • 165+ EA Score Guarantee
  • 4,100+ Quant, Verbal, and Integrated Reasoning practice questions
  • 400+ hours of in-depth video lessons
  • 3,000+ step-by-step video solutions
View EA class & enroll Start free 5-day trial
Limited cohort · enrollment openTrial includes full course accessTarget Test Prep
GMATOnDemandStart anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

715+ score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions

perimeter of the shaded region

Expert replies
by jain2016 » Tue Apr 19, 2016 8:58 am
In the figure to the right, circle O has center O, diameter AB and a radius of 5. Line CD is parallel to the diameter. What is the perimeter of the shaded region?

A) (5/3)pie + 5 under root 3

B) (5/3)pie + 10 under root 3

C) (10/3)pie + 5 under root 3

D) (10/3)pie + 10 under root 3

E) (10/3)pie + 20 under root 3

OAD

Hi Experts ,

Please explain.

Many thanks in advance.

SJ
You do not have the required permissions to view the files attached to this post.
Join the discussion
Source: — Problem Solving |

by Ides_of_marzo » Tue Apr 19, 2016 9:19 am
Do you mean root 3 or root 2?
Join the discussion

by Brent@GMATPrepNow » Tue Apr 19, 2016 9:19 am
In the figure to the right, circle O has center O, diameter AB and a radius of 5. Line CD is parallel to the diameter. What is the perimeter of the shaded region?

A. (5/3)pi + 5√3
B. (5/3)pi + 10√3
C. (10/3)pi + 5√3
D. (10/3)pi + 10√3
E. (10/3)pi + 20√3

Image

IMPORTANT: unless stated otherwise, the diagrams in Problem Solving geometry questions are DRAWN TO SCALE.
For more on this, see our free video: https://www.gmatprepnow.com/module/gmat- ... /video/863

I'll solve this question using estimation.
Since the diameter AB = 10, we can ESTIMATE the length of CB.
It looks like CB is just a little bit shorter than AB.
So, I'll say that the length of side CB is approximately 9.
This means the length of side EB is approximately 9 as well.
Finally, arc EC looks a little bit shorter than sides CB and EB, so I'll estimate it to be length 8

So, the TOTAL perimeter = 9 + 9 + 8 = 26

Now check the answer choices:

ASIDE: On test day, everyone should know the following apprximations:
√2 ≈ 1.4
√3 ≈ 1.7
√5 ≈ 2.2
Also, we'll say that pi ≈ 3


A. (5/3)pi + 5√3 ≈ 5 + 8.5 ≈ 13.5
B. (5/3)pi + 10√3 ≈ 5 + 17 ≈ 22
C. (10/3)pi + 5√3 ≈ 10 + 8.5 ≈ 18.5
D. (10/3)pi + 10√3 ≈ 10 + 17 ≈ 27
E. (10/3)pi + 20√3 ≈ 10 + 34 ≈ 44

Of these, it appears that D is the closest.

Aside: We can see that answer choice B is pretty close too. At this point, you have a time-management decision. You can either stick with D, and use your extra time elsewhere, or your can spend time trying to be more certain of the answer. Your choice.

That said, D is the correct answer.

Cheers,
Brent
Brent Hanneson - Creator of GMATPrepNow.com
Image
Join the discussion

by OptimusPrep » Tue Apr 19, 2016 8:27 pm
jain2016 wrote:In the figure to the right, circle O has center O, diameter AB and a radius of 5. Line CD is parallel to the diameter. What is the perimeter of the shaded region?

A) (5/3)pie + 5 under root 3

B) (5/3)pie + 10 under root 3

C) (10/3)pie + 5 under root 3

D) (10/3)pie + 10 under root 3

E) (10/3)pie + 20 under root 3

OAD

Hi Experts ,

Please explain.

Many thanks in advance.

SJ
Let us first find the angles related to the perimeter
Since CD is parallel yo AB, therefore angle CBA = 30 and angle CBE = 60
Now from the property of the circle, angle at centre is twice the angle at circumference
angle COE = 2*angle CBE
Therefore angle COE = 120

Now let us try and find the lengths.
arc CAE = 1/3 (2*pi*5) {Since 120 = 360/3}
arc CAE = (10/3)*pi

Now coming to the sides,
Draw a line from C to O.
In the triangle COB, we have CO = OB = 5 (radius of the circle)
If we drop a perpendicular from OP on CB, we will have triangles OPB and OPC and PB = PC

In triangle OPB, we know that OB = 5
angle OBP = 30, angle OPB = 90
Cos 30 = PB/OB
√3/2 = PB/5
Therefore PB = 5√3/2

Hence CB = PB + PC = 5√3

Therefore the total parameter = arc CAE + CB + EB = 2*(5√3) + (10/3)*pi = (10/3)*pi + 10√3

Correct Option: D
You do not have the required permissions to view the files attached to this post.
Join the discussion