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by ssmiles08 » Tue May 26, 2009 6:30 am
It is a 30-60-90 triangle so PS = 4 and PQ = 8

SInce it is a equilateral triangle, 8*3 = 24
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Thank you

by ST » Tue May 26, 2009 6:33 am
Thank you
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by gmat740 » Tue May 26, 2009 12:29 pm
I doubt the solution

In an equilateral triangle :

Altitude or Height = sqrt(3)/2 times of a

where a= side of the equilateral triangle(this can be easily proved with the help of trigonometry)

So 4/sqrt(3) = [sqrt(3)/2]*a

a = 8/3

So perimeter = 3a = 8

Please check again

Thanks
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by dumb.doofus » Tue May 26, 2009 1:28 pm
gmat740 wrote:I doubt the solution

In an equilateral triangle :

Altitude or Height = sqrt(3)/2 times of a

where a= side of the equilateral triangle(this can be easily proved with the help of trigonometry)

So 4/sqrt(3) = [sqrt(3)/2]*a

a = 8/3

So perimeter = 3a = 8

Please check again

Thanks
Bold statement above .. incorrectly written.. its 4root(3) and not 4/root(3)
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by gmat740 » Tue May 26, 2009 6:49 pm
Oh!
Silly Mistake!
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