Live GMAT classes with Target Test Prep start Nov 21 and Nov 22. First class free.

See classes
Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

Newsweek Readers’ Choice Awards 2026 winner: Target Test Prep, #1 Test Prep

Target Test Prep was voted #1 Best Test Prep in the 2026 Newsweek Readers’ Choice™ Awards.

★★★★★5.0563 reviews
GMATLiveTeachStarts Nov 22
Josh Braslow, Target Test Prep GMAT expert
LIVE ONLINE CLASSES

Get Ready for GMAT Test Day Faster with Live Online Classes

with Josh Braslow, 20+ years in test prep

Nov 22 · Josh Braslow
Sun · 9:30 AM to 12:30 PM ET
Included
40 hours of live online classes + 6 months of TTP OnDemand
  • Attend the first class for free
  • Every class is recorded, so you never fall behind
View classes & enroll
Limited seats availableTarget Test Prep
EALiveTeachOnDemandStart anytime
EXECUTIVE ASSESSMENT

Target Test Prep EA OnDemand

Self-paced EA prep. Study on your schedule.

EXECUTIVE ASSESSMENT

with

165+ EA score guarantee
$05-day trial no automatic billing
Schedule
Included
40 hours of live online classes plus six months of access to the complete TTP EA OnDemand course.
  • 165+ EA Score Guarantee
  • 4,100+ Quant, Verbal, and Integrated Reasoning practice questions
  • 400+ hours of in-depth video lessons
  • 3,000+ step-by-step video solutions
View EA class & enroll Start free 5-day trial
Limited cohort · enrollment openTrial includes full course accessTarget Test Prep
GMATOnDemandStart anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

715+ score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions
Start free 5-day trial
Read 563 reviewsTarget Test Prep

Percents/Algebra Word Translation

Expert replies
Post new topic Post Reply
Subscribe topic
Previous Topic Next Topic
Senior | Next Rank: 100 Posts
Posts: 76
Joined: Thu Feb 19, 2009 12:10 pmFollowed by: 2 members
Thanked: 3 times
by Bens4vcobra » Tue Jul 05, 2011 6:02 am
A collage admissions officer predicts 20% of students who are accepted will not attend college. According to this prediction, how many students should be accepted to achieve a planned enrollment of x students?

A) 1.05x

B) 1.1x

C) 1.2x

D) 1.25x

E) 1.8x
"It takes no ability to give effort. Toughness is not God-given; it's a choice. The discipline to execute is a habit." - Nick Saban
Top
Join the discussion
Source: — Problem Solving |
Legendary Member
Posts: 1448
Joined: Tue May 17, 2011 9:55 amFollowed by: 53 members
Location: India
Thanked: 375 times

by Frankenstein » Tue Jul 05, 2011 6:38 am
Hi,
If n are accepted, 0.8n will attend(enroll)
So, for x to be enrolled, x = 0.8n =>n =1.25x

Hence, D
Cheers!

Things are not what they appear to be... nor are they otherwise
Top
Join the discussion
Junior | Next Rank: 30 Posts
Posts: 21
Joined: Sun Jun 05, 2011 10:39 pmFollowed by: 1 member
Thanked: 2 times

by worldpeace93 » Tue Jul 05, 2011 8:30 am
answer is 1/(1-1/5)=1.2
Top
Join the discussion
Senior | Next Rank: 100 Posts
Posts: 76
Joined: Thu Feb 19, 2009 12:10 pmFollowed by: 2 members
Thanked: 3 times

by Bens4vcobra » Tue Jul 05, 2011 9:17 am
worldpeace93 wrote:answer is 1/(1-1/5)=1.2
This is what I thought as well. But the correct answer is 1.25x.
"It takes no ability to give effort. Toughness is not God-given; it's a choice. The discipline to execute is a habit." - Nick Saban
Top
Join the discussion
Legendary Member
Posts: 1448
Joined: Tue May 17, 2011 9:55 amFollowed by: 53 members
Location: India
Thanked: 375 times

by Frankenstein » Tue Jul 05, 2011 9:28 am
Bens4vcobra wrote:
worldpeace93 wrote:answer is 1/(1-1/5)=1.2
This is what I thought as well. But the correct answer is 1.25x.
Hi,
Both of you must have made calculation mistakes.
1/(1-1/5) = 1/(4/5) = 5/4 = 1.25
Cheers!

Things are not what they appear to be... nor are they otherwise
Top
Join the discussion
Master | Next Rank: 500 Posts
Posts: 152
Joined: Wed Mar 12, 2008 4:36 pmFollowed by: 2 members
Thanked: 8 times

by artistocrat » Tue Jul 05, 2011 6:30 pm
This is like a 500-600 level question.
Top
Join the discussion
Senior | Next Rank: 100 Posts
Posts: 76
Joined: Thu Feb 19, 2009 12:10 pmFollowed by: 2 members
Thanked: 3 times

by Bens4vcobra » Wed Jul 06, 2011 5:50 am
Frankenstein wrote:
Bens4vcobra wrote:
worldpeace93 wrote:answer is 1/(1-1/5)=1.2
This is what I thought as well. But the correct answer is 1.25x.
Hi,
Both of you must have made calculation mistakes.
1/(1-1/5) = 1/(4/5) = 5/4 = 1.25
Could you explain how you came up with "1/(1-1/5)" ? I understand the calculation you performed, however, I'm not understanding where you get your methodology.
"It takes no ability to give effort. Toughness is not God-given; it's a choice. The discipline to execute is a habit." - Nick Saban
Top
Join the discussion
Master | Next Rank: 500 Posts
Posts: 152
Joined: Wed Mar 12, 2008 4:36 pmFollowed by: 2 members
Thanked: 8 times

by artistocrat » Wed Jul 06, 2011 9:28 am
Bens4vcobra wrote:A collage admissions officer predicts 20% of students who are accepted will not attend college. According to this prediction, how many students should be accepted to achieve a planned enrollment of x students?

A) 1.05x

B) 1.1x

C) 1.2x

D) 1.25x

E) 1.8x
Instead of doing calculations, just pick numbers. Say the target number of students is 100 (x=100), then you would have to accept 125, because 25 or 20% of 125 will not attend.
Top
Join the discussion