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percentage problem

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by wawatan » Sun May 25, 2008 2:47 pm
A doctor prescribed 18 cubic centimeters of a certain drug to a patient whose body weight was 120 pounds. If the typical dosage is 2 cubic centimeters per 15 pounds of body weight, by what percent was the prescribed dosage greater than the typical dosage?

8
9
11
12.5
14.8

OA is D
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by aatech » Sun May 25, 2008 6:38 pm
For 15 pounds of weight 2 CC of medicine is required,

so for 120 pounds 2*120/15 = 16 cc of medicine is required

Doctor prescribed 18 cc

% extra = 2*100/16 = 12.5
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by ildude02 » Tue May 27, 2008 5:12 pm
aatech wrote:For 15 pounds of weight 2 CC of medicine is required,

so for 120 pounds 2*120/15 = 16 cc of medicine is required

Doctor prescribed 18 cc

% extra = 2*100/16 = 12.5
Why is it not 2*100/18 ?? Do we normally treat this kind of question like a
%increase, where the denominator is always the lowest of the 2 values?

Otherwise, I would have had an equation like this,

x/100 * 18 = 18-16.
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by netigen » Tue May 27, 2008 8:20 pm
you will calculate the increase over what the dosage should have been i.e. over 16

since overage is 2 the eq is 2/16 x 100 = 12.5
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