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Percentage problem -1

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by guerrero » Tue Mar 19, 2013 1:00 pm
Marketing executives for a certain chewing gum company projected a 20 percent increase in revenue this year over that of last year, but revenue this year actually decreased by 25%. What percent of the projected revenue was the actual revenue ?

A)53%
B)58%
c)62.5%
D)64%
E)75%
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by GMATGuruNY » Tue Mar 19, 2013 1:25 pm
guerrero wrote:Marketing executives for a certain chewing gum company projected a 20 percent increase in revenue this year over that of last year, but revenue this year actually decreased by 25%. What percent of the projected revenue was the actual revenue ?

A)53%
B)58%
c)62.5%
D)64%
E)75%
Let last year's revenue = 100.
Since a 20% increase was projected, the projected revenue = 100 + .2(100) = 120.
Since the actual revenue decreased by 25%, the actual revenue = 100 - .25(100) = 75.
Thus, actual revenue/projected revenue = 75/120 = 5/8 = 62.5%.

The correct answer is C.
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by rairavig » Wed Mar 20, 2013 2:28 am
let the revenue for last year is 'x'
projected revenue is x + .2x
actual revenue is x - .25x

the projected revenue was the actual revenue = actual revenue/projected revenue is x + .2x

= x - .25x / x + .2x
= x (1-.25) / x(1+.2)
= 1-.25 / 1+.2
= .75 / 1.2
= .625
in % it would come 62.5%
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Re: Percentage problem -1

by Scott@TargetTestPrep » Tue Jan 21, 2020 7:57 am
guerrero wrote: ↑
Tue Mar 19, 2013 1:00 pm
 Marketing executives for a certain chewing gum company projected a 20 percent increase in revenue this year over that of last year, but revenue this year actually decreased by 25%. What percent of the projected revenue was the actual revenue ?

A)53%
B)58%
c)62.5%
D)64%
E)75%
We can let the revenue last year = 100.

Projected revenue was 1.2 x 100 = 120, and actual revenue was 100 x 0.75 = 75.

Thus, actual/projected = 75/120 = 25/40 = ⅝ = 62.5%.

Answer: C

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