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My answer (C)goyalsau wrote:In the xy-plane, if points (5, 2), (2, 5), and (-2, -5) are the vertex of a parallelogram, how many such parallelograms are possible?
(A) 1
(B) 2
(C) 3
(D) 4
(E) 6
goyalsau wrote:In the xy-plane, if points (5, 2), (2, 5), and (-2, -5) are the vertex of a parallelogram, how many such parallelograms are possible?
(A) 1
(B) 2
(C) 3
(D) 4
(E) 6
Thanks Rahul for the figure but , I am not able to understand it completely Please explain with some detail so i can understand it.Rahul@gurome wrote:goyalsau wrote:In the xy-plane, if points (5, 2), (2, 5), and (-2, -5) are the vertex of a parallelogram, how many such parallelograms are possible?
(A) 1
(B) 2
(C) 3
(D) 4
(E) 6
See the above image.
For three non collinear points in a plane always only three parallelograms can be drawn with those points as vertex.
The correct answer is C.
Goyal try drawing the xy coordinate plan and then plot those points.Join those points and form a triangle.Rahul's concept is based on keeping each side once as a diagonal and the other 2 as one of the 2 parallel sides.goyalsau wrote:Thanks Rahul for the figure but , I am not able to understand it completely Please explain with some detail so i can understand it.Rahul@gurome wrote:goyalsau wrote:In the xy-plane, if points (5, 2), (2, 5), and (-2, -5) are the vertex of a parallelogram, how many such parallelograms are possible?
(A) 1
(B) 2
(C) 3
(D) 4
(E) 6
See the above image.
For three non collinear points in a plane always only three parallelograms can be drawn with those points as vertex.
The correct answer is C.
In the figure, points A, B and C are any three given points in a plane which are non-collinear. Points O, P and Q are possible points each of which with A, B and C gives rise to a parallelogram. Thus the possible parallelograms are OBCA, ABCQ and ABPC.goyalsau wrote:Thanks Rahul for the figure but , I am not able to understand it completely Please explain with some detail so i can understand it.
The question is based on simple knowledge of geometry (to be precise concept of parallel lines) and can be answered applying the concept. If you insist then combinatorics can be applied as follows,rishab1988 wrote:rahul it would be great if you could shed some light on whether combinatorics can be used to solve this question,because what you showed was quite intuitive and might not have been thought of others.
