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GMAT Prep 2 - Decimals

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by pradeepspanchal » Mon Dec 13, 2010 9:25 pm
Image


Although , it may be piece of cake for you , I got a doubt here.

In option A, the rounded value up-to thousandth is give, The thousandth value is 5 and hence the hundrth value will be increase by one , therefor .455 will become .46 and hence the result. and answer A .

As per my knowledge , if the last digit is either 5 or greater leads to the rounding and next number become one higher. eg . .457 after rounding to hundredth will become .46.

Because I got an incorrect answer , surly I in the wrong boat. Please highlight the mistake.
Thanks in advance
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by prachich1987 » Mon Dec 13, 2010 9:59 pm
pradeepspanchal wrote:Image


Although , it may be piece of cake for you , I got a doubt here.

In option A, the rounded value up-to thousandth is give, The thousandth value is 5 and hence the hundrth value will be increase by one , therefor .455 will become .46 and hence the result. and answer A .

As per my knowledge , if the last digit is either 5 or greater leads to the rounding and next number become one higher. eg . .457 after rounding to hundredth will become .46.

Because I got an incorrect answer , surly I in the wrong boat. Please highlight the mistake.
Thanks in advance
According to me the answer should be A.
From first statement, we can clearly conclude that x will be 0.46 after rounding to hundredth value
& it alone is sufficient unlike the 2nd one

But definitely we are doing something wrong.
Sm1 plz help
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by goyalsau » Mon Dec 13, 2010 11:21 pm
pradeepspanchal wrote:
the rounded value up-to thousandth is give, The thousandth value is 5 and hence the hundrth value will be increase by one , therefor .455 will become .46 and hence the result. and answer A .
Ist statement
It says when rounded to nearest thousand then the result is .455 , value of x could be .4549 or .4551

When x is .4549, Rounded to nearest 100th then it is .45

when x is .4551 , Rounded to nearest 100th then it is .46

In sufficient

2nd Statement thousandth digit is 5,

This statement Confused me, Question says What is the result when x is rounded to nearest 100th, Now we know that thousandth digit is 5 so, when rounded to nearest 100th , it will definitely be +1 for 100th digit, No matter what is the digit at 100th place.

We know the result must be +1 on hundredth digit, According to me it should be sufficient.

I just don't understand why they need the value of x from 1st statement...............??????



x can be .455 or .445 or .435
Nothing particular
so insufficient
Saurabh Goyal
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by prachich1987 » Mon Dec 13, 2010 11:38 pm
goyalsau wrote:
pradeepspanchal wrote:
the rounded value up-to thousandth is give, The thousandth value is 5 and hence the hundrth value will be increase by one , therefor .455 will become .46 and hence the result. and answer A .
Ist statement
It says when rounded to nearest thousand then the result is .455 , value of x could be .4549 or .4551

When x is .4549, Rounded to nearest 100th then it is .45

when x is .4551 , Rounded to nearest 100th then it is .46

In sufficient

2nd Statement thousandth digit is 5,

This statement Confused me, Question says What is the result when x is rounded to nearest 100th, Now we know that thousandth digit is 5 so, when rounded to nearest 100th , it will definitely be +1 for 100th digit, No matter what is the digit at 100th place.

We know the result must be +1 on hundredth digit, According to me it should be sufficient.

I just don't understand why they need the value of x from 1st statement...............??????



x can be .455 or .445 or .435
Nothing particular
so insufficient
I am a bit confused b the procedure of rounding the digits
I didn't understand the below
"When x is .4549, Rounded to nearest 100th then it is .45"
Is it right? According to me it should be 0.46 only.
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by goyalsau » Mon Dec 13, 2010 11:41 pm
prachich1987 wrote: I am a bit confused b the procedure of rounding the digits
I didn't understand the below
"When x is .4549, Rounded to nearest 100th then it is .45"
Is it right? According to me it should be 0.46 only.

go through this link it will be helpful for you.

https://mathforum.org/library/drmath/view/58938.html
Saurabh Goyal
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by prachich1987 » Mon Dec 13, 2010 11:48 pm
goyalsau wrote:
prachich1987 wrote: I am a bit confused b the procedure of rounding the digits
I didn't understand the below
"When x is .4549, Rounded to nearest 100th then it is .45"
Is it right? According to me it should be 0.46 only.

go through this link it will be helpful for you.

https://mathforum.org/library/drmath/view/58938.html
Thanks it was really helpful
my all doubts regarding rounding are clear now. :)
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by pradeepspanchal » Mon Dec 13, 2010 11:52 pm
Thanks goyalsau, prachich1987. good link . Intialy, I though we have to round off from the last digit and keep rounding off until the intended digit.
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by abhishekg21 » Tue Dec 14, 2010 5:50 am
whats the OA for this ?
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by pradeepspanchal » Tue Dec 14, 2010 7:53 am
OA is C, its in picture.
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