answer is D. how
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I think some scenarios are missed in the above reasoning.shalen78 wrote:P, P+4, P+11 = 3 P +15
or
P+5 = Even Number
therefore
P must be odd and the first equation is sufficient
P - 3, P, P +11
3P + 8 = odd
If P is 1...you can have 11, P is 3 you can have 13...1,3 and any odd number satisfies the 2nd condition.
Therefore the 2nd equation is also sufficient.
yeps...u r right...i read the first scenario as P = even...shalen78 wrote:P can not be an even number in Statement 1 (it invalidates the condition).
If P is even, i.e. 4...the sum of P, P+4, P+11 is equal to 4+8+15 = 27. This is not what statement 1 says. Statement 1 says that the sum of P, P+4 and P+11 must equal some even number.
If P is odd, i.e. 5 the sum of P, P+4, P+11 is equal to 5+9+16 = 30. This is exactly what Statement 1 tells you. The sum of the P, P +4 and P + 11 equals some EVEN number.