Anurag@Gurome wrote: In the original papayaya drink, soda water = 4/7, natural lemon juice = 1/3, remaining ingredients = 1 - (4/7 + 1/3) = 1 - 19/21 = 2/21
Since, amounts of sugar and papaya puree in Papayaya are equal, so sugar = 1/21 and papaya puree = 1/21
After malfunctioning, soda water = 4/7, natural lemon juice = 2/3, sugar = 1/21 and papaya puree = 3/21 = 1/7
Therefore, fractional portion of soda water in the drink that comes out of the malfunctioning machine = 4/7 / (4/7 + 2/3 + 1/21 + 3/21) = 4/7 / 30/21 = [spoiler]2/5[/spoiler]

The correct answer is C.

patanjali.purpose wrote:Papayaya, a popular soft drink, contains only four ingredients. Soda water comprise 4/7 of Papayaya and natural lemon juice makes 1/3 of Papayaya. The amounts of sugar and papaya puree in Papayaya are equal. Due to a malfunction, the mixing machine mixes double the regular amount of lemon juice and three times the regular amount of papaya puree. If no other changes were made to the relative quantities of the ingredients, what is the fractional portion of soda water in the drink that comes out of the malfunctioning machine?

A) 7/30
B) 7/21
C) 2/5
D) 12/29
E) 4/7

GMATGuruNY wrote:
Before the malfunction:
Let the total = 42 units.
Soda = (4/7)42 = 24 units.
Lemon juice = (1/3)42 = 14 units.
Remaining units = 42-24-14 = 4 units.
Dividing the remaining units equally between the sugar and the papaya:
Sugar = 2 units.
Papaya = 2 units.

After the malfunction:
Lemon juice doubled = 2*14 = 28 units.
Papaya tripled = 3*2 = 6 units.
New total = soda + new lemon + sugar + new papaya = 24+28+2+6 = 60 units.
Soda/total = 24/60 = 2/5.

The correct answer is C.