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Expert replies
by divyalr » Tue Oct 13, 2009 7:04 pm
If 20% of the people at a college party were men who were wearing red t-shirts, and 60% of the men at the party were not wearing red t-shirts, what percent of the people at the party were men?

(A) 80 %
(B) 60 %
(C) 50 %
(D) 40 %
(E) 33 1/3 %

I got answer C. Can anyone verify?

Let # of people at party = x
Let # of men at the party = m
.2x = .4m
m/x= 1/2
Question asked : %/100 * x = m
% = 100*m/x = 100*1/2 = 50 ( answer c)
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Source: — Problem Solving |

by grockit_jake » Wed Oct 14, 2009 12:57 pm
It may help to use absolute numbers instead of percentages. We'd use 100, since that's the best with %s.

100 total
20 red shirt + man
40% of men had red T-shirts.

2/5M = 20
M=50

Your way looks correct to me. You can do it algebraically like you did, or use absolutes and plug in where possible. Whatever makes more sense to you.
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