BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

★★★★★5.0559 reviews
Vote for Target Test Prep, Newsweek Readers’ Choice Awards 2026
NEWSWEEK READERS’ CHOICE 2026

BIG NEWS! Target Test Prep has been nominated, and they’d love your vote!

TTP has worked incredibly hard to build the best test prep experience possible, and winning Newsweek’s 2026 Readers’ Choice Award for Best Test Prep would mean a lot to them. If TTP has helped you, they’d be incredibly grateful for your vote. You can vote once each day through September 9.

Vote for TTP
GMATLiveTeach 7 seats left
Chris Peckover
NEXT LIVE COHORT

Oct 13 to Jan 7, 2027

with Chris Peckover

Schedule
Tue, Thu · 8:00 to 10:00 PM ET
Included
40 live hours + 6 months of GMAT OnDemand
  • Live instruction and real-time questions
  • Class recordings and assigned practice
View class & enroll
Limited cohort · enrollment openTarget Test Prep
EALiveTeach 5 seats left
Logan Thompson
EXECUTIVE ASSESSMENT

Sep 6 to Dec 6, 2026

with Logan Thompson

Schedule
Sun · 9:30 AM to 12:30 PM ET
Included
40 hours of live online classes plus six months of access to the complete TTP EA OnDemand course.
  • 165+ EA Score Guarantee
  • 4,100+ Quant, Verbal, and Integrated Reasoning practice questions
  • 400+ hours of in-depth video lessons
  • 3,000+ step-by-step video solutions
View EA class & enroll
Limited cohort · enrollment openTarget Test Prep
GMATOnDemand Start anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

715+ score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions

Compare the format, schedule, and included access before enrolling. Prices and seat counts shown reflect the supplied offer details.

P,Q,R,S

Expert replies
by harsh.champ » Tue Feb 09, 2010 5:43 am
What is the value of (2P + Q) if it is divisible by 4? (Here, each of P, Q, R and S are positive integers)


A: P x Q = 2.
B: P + Q + R + S = 6 and R > S.

[spoiler]
Using statement A:
Since each of P, Q, R and S are positive integers and
P x Q = 2, then P and Q are either 1 or 2 respectively.
But since it is given that (2P + Q) is divisible by 4, P and Q
cannot be equal to 2 and 1 respectively.
Therefore, P = 1 and Q = 2.
Hence, statement A alone is sufficient to answer the question.
Using statement B:
Please note that neither of P, Q, R and S can take values 6, 5,
4 or 3. (Since, P + Q + R + S = 6)
Now, since R > S, R should be 2 and S should be 1.
Similarly, P = 1 and Q = 2 as (2P + Q) is divisible by 4.
Hence, statement B alone is sufficient to answer the question.[/spoiler]
It takes time and effort to explain, so if my comment helped you please press Thanks button :)



Just because something is hard doesn't mean you shouldn't try,it means you should just try harder.

"Keep Walking" - Johnny Walker :P
Join the discussion
Source: — Data Sufficiency |

by shashank.ism » Tue Feb 09, 2010 5:52 am
harsh.champ wrote:What is the value of (2P + Q) if it is divisible by 4? (Here, each of P, Q, R and S are positive integers)


A: P x Q = 2.
B: P + Q + R + S = 6 and R > S.

[spoiler]
Using statement A:
Since each of P, Q, R and S are positive integers and
P x Q = 2, then P and Q are either 1 or 2 respectively.
But since it is given that (2P + Q) is divisible by 4, P and Q
cannot be equal to 2 and 1 respectively.
Therefore, P = 1 and Q = 2.
Hence, statement A alone is sufficient to answer the question.
Using statement B:
Please note that neither of P, Q, R and S can take values 6, 5,
4 or 3. (Since, P + Q + R + S = 6)
Now, since R > S, R should be 2 and S should be 1.
Similarly, P = 1 and Q = 2 as (2P + Q) is divisible by 4.
Hence, statement B alone is sufficient to answer the question.[/spoiler]
2P+Q is even so q must be even
A.) P x Q = 2. either p or q= 2 q is even q=2 and p=1
B.)P+Q+R+S =6 R>S Q =2or 4 or 6 but 2 is only possible as P, Q,s are also integer
So P+R+S=4
r>S
and combination is 1+1+2=4
so r=2, s=p=1
so p=1,q=2

ans D
My Websites:
www.mba.webmaggu.com - India's social Network for MBA Aspirants

www.deal.webmaggu.com -India's online discount, coupon, free stuff informer.

www.dictionary.webmaggu.com - A compact free online dictionary with images.

Nothing is Impossible, even Impossible says I'm possible.
Join the discussion

by ajith » Tue Feb 09, 2010 7:29 am
harsh.champ wrote:What is the value of (2P + Q) if it is divisible by 4? (Here, each of P, Q, R and S are positive integers)


A: P x Q = 2.
B: P + Q + R + S = 6 and R > S.
1) P*Q =2

P =2 and Q =1; 2P+Q = 5

or

P= 1 am Q =2 ; 2P+Q =4

Suffiicient


2) P + Q + R + S = 6

R+S =>3

P+Q =< 3

2P+Q is a multiple of 3

Q =1 and P=1 is not possible since 2P+Q is not a multiple of 4
Q=2 P=1 is the ony option

Sufficient



At this precise moment I will
Always borrow money from a pessimist, he doesn't expect to be paid back.
Join the discussion