P problem

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pradeepkaushal9518: Legendary Member; Posts: 1309; Joined: Wed Mar 17, 2010 11:41 pmFollowed by: 5 members; Thanked: 33 times

by pradeepkaushal9518 » Sat Apr 17, 2010 10:26 pm

Given that p is a positive even integer with a positive units digit, if the units digit of p3 minus the units digit of p2 is equal to 0, what is the units digit of p + 3?

i dont have OA

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Source: Beat The GMAT — Problem Solving | Sat Apr 17, 2010 10:26 pm

eaakbari: Master | Next Rank: 500 Posts; Posts: 435; Joined: Mon Mar 15, 2010 6:15 amFollowed by: 1 member; Thanked: 32 times

by eaakbari » Sat Apr 17, 2010 10:46 pm

Asumming your question was p^3-p^2 and not 3p-2p

Since units of p^3 -P^2 = 0

Units digit of p^3 and p^2 is the same

It can be one of the following
2
4
6
8

As these are even and positive

Out of all only 6 satisfies condition.

Hence units p = 6
units p +3
= 9
IMO 9

Whether you think you can or can't, you're right.
- Henry Ford

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pradeepkaushal9518: Legendary Member; Posts: 1309; Joined: Wed Mar 17, 2010 11:41 pmFollowed by: 5 members; Thanked: 33 times

by pradeepkaushal9518 » Sat Apr 17, 2010 11:12 pm

sir why not 10 which also satisfy the condition

10^3=1000
10^2=100
1000-100=900

that is main question i think?

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eaakbari: Master | Next Rank: 500 Posts; Posts: 435; Joined: Mon Mar 15, 2010 6:15 amFollowed by: 1 member; Thanked: 32 times

by eaakbari » Sat Apr 17, 2010 11:36 pm

pradeepkaushal9518 wrote:sir why not 10 which also satisfy the condition

10^3=1000
10^2=100
1000-100=900

that is main question i think?

Kya Sir bula raha hain yaar,

Given that p is a positive even integer with a positive units digit

Since units digit is a positive integer, 0 is neither positive nor negative. Hence it cannot be 0.

HTH

Whether you think you can or can't, you're right.
- Henry Ford

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pradeepkaushal9518: Legendary Member; Posts: 1309; Joined: Wed Mar 17, 2010 11:41 pmFollowed by: 5 members; Thanked: 33 times

by pradeepkaushal9518 » Sun Apr 18, 2010 4:03 am

ok now it is clear. do i know you ?

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eaakbari: Master | Next Rank: 500 Posts; Posts: 435; Joined: Mon Mar 15, 2010 6:15 amFollowed by: 1 member; Thanked: 32 times

by eaakbari » Sun Apr 18, 2010 4:05 am

pradeepkaushal9518 wrote:ok now it is clear. do i know you ?

Well i guess not, unless you know Ebrahim Akbari.

Whether you think you can or can't, you're right.
- Henry Ford

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