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\(p\) is the smallest perfect cube greater than \(1\) such that the difference between the tens digit of \(p^2\) and the

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\(p\) is the smallest perfect cube greater than \(1\) such that the difference between the tens digit of \(p^2\) and the

by Gmat_mission » Sun Mar 14, 2021 5:41 am

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\(p\) is the smallest perfect cube greater than \(1\) such that the difference between the tens digit of \(p^2\) and the unit digit of \(p^2\) is \(2.\) If \(Z=1\cdot 2\cdot 3 \cdots p,\) then the total number of factors of \(Z\) is

A. 5
B. 8
C. 14
D. 96
E. 192

Answer: D

Source: e-GMAT
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