Q 10 positive numbers n1<n2<... <n10. how many triplets can be chosen such that they shd be in ascending order.
a)45
b)90
c)120
d)180
a)45
b)90
c)120
d)180
3 numbers can be chosen from 10 +ve integers in 10C3 = 120 ways
Now after choosing 3 numbers, there is only 1 way to arrange them (ascending order)
Answer = 120*1 = 120
