P&C

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Source: — Data Sufficiency |

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by cans » Wed Sep 07, 2011 5:16 am
consonants = 4
arrange them = 24 ways.
vowels = 3. arrange them = 6 ways.
also 5 spaces in consonants. pick any 3 . 5C3
24*6*10 =1440
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by sl750 » Thu Sep 08, 2011 8:03 am
Why is it 5c3?

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by knight247 » Thu Sep 08, 2011 8:42 am
The arrangement looks as follows. Where the three vowels can only be fitted in one of the gaps

_P_R_V_T_

Firstly, the 3 vowels can be placed and shuffled in any of the 5 gaps in 5P3=60Ways
The four consonants can be adjusted amongst themselves in 4P4=4!=24 Ways

Total number of ways=24*60=1440 ways Hence D