P & C

Since the problem does not restrict whether the 3 digits has to be a 3 digit number, it can be assumed that numbers starting from 0 are also acceptable.

however, the official solution of 10 is incorrect. This is because the last digit can be any one of 5 and the other 2 digits can be any of 10. so the number of apparels is 10*10*5 = 500.

If we consider that the number has to be a valid 3 digit number, then hundred's digit can be any of 9 and ten's digit can be any of 10 and unit's digit can be any of 5. So total apparels = 9*10*5 = 450

Thanks Brent

Brent@GMATPrepNow wrote:

shekhar.kataria wrote:Mark’s clothing store uses a bar-code system to identify every item. Each item is marked by a combination of 2 letters followed by 3 digits.Additionally, the three-digit number must be even for male products and odd for female products. If all apparel products start with the letter combination AP, how many male apparel items can be identified with the bar code?

Given Solution [spoiler]1*10*10*5[/spoiler]

My Doubt The Red coloured highlighted value should be 9 because hundredth digit cant have zero. If so this will be a 2 digit code.

Typically, a 3-digit number implies that the hundreds digit is not zero.
However, in this instance, it sounds like a code like AP034 may be acceptable, in which case the given answer is correct.
If a code like AP034 is not acceptable, then your solution is correct.

That said, the GMAT test-makers are the best at framing questions so that they eliminate any ambiguous interpretations. So, as it stands, this would not be an official question (without the addition of some text that removes ambiguity.)

Cheers,
Brent