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Out for a Run - GMATPrep

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Senior | Next Rank: 100 Posts
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Re: Out for a Run - GmatPrep

by msd_2008 » Sun Jul 06, 2008 11:13 pm
Can you tell me whats the correct answer for the question?

Thanks
MSD
When the going gets tough, the tough gets going.
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by P_mashru » Mon Jul 07, 2008 12:15 am
Total periphery = 2 pie r = 2x22/7x1 = 6.38 miles

avg rate = 3 miles / hr

it would take more than 2 hrs for johanna to complete the circle

Answer is c - 2<t<2.5

what is OA :?:
I am I
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by vishubn » Mon Jul 07, 2008 1:24 am
Hi

Answer is C

Catch point " Walked Once" ....

So the length is = 2 pi r = 6.28 miles
time=distance/speed 6.28/3=2.09

t > 2 but t<2.5


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by AleksandrM » Mon Jul 07, 2008 2:05 pm
I did not convert pi to 3.14, which is why I got the wrong answer. Thank you all.
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