Hi,

Let us look at statement 2:

If x >0 and we know that x^3 < x^2, then we can say that 0<x<1

To elaborate, the behavior of x^3 and x^2 across the different values of x are as follows:


==========

When x<0, x^3 < x^2

When x = 0, x^3 = x^2

When 0<x<1, x^3 < x^2

When x = 1, x^3 = x^2

When x > 1, x^3 > x^2


==========

Hence, the answer is D indeed ... Hope this helps.

Thanks.

adi_800 wrote:If x > 0, is x^2 < x ?
(1) 0.1 < x < 0.4
(2) x^3 < x^2

[spoiler]OA is D..
I got A[/spoiler]

is x^2 < x ?
is x^2-x<0
is x(x-1)<0?
Which means the question is asking is x<0 or x<1

Now,
(1) 0.1 < x < 0.4
clearly x<1. Hence SUFF

(2) x^3 < x^2
x^3-x^2<0
x^2(x-1)<0
x^2 canot be less than 0.
hence x-1<0
x<1
hence SUFF

pick D.

Hope this helps!!

adi_800 wrote:If x > 0, is x^2 < x ?
(1) 0.1 < x < 0.4
(2) x^3 < x^2

[spoiler]OA is D..
I got A[/spoiler]

Don't know what you did adi, but I get (D).

We are simply checking whether X is a fraction or not by checking this --> x^2 < x

(1) 0.1 < x < 0.4

X is clearly a fraction because its between 0 and 1.

(2) x^3 < x^2

Since 3 x's are smaller than 2 x's, it HAS to be a fraction. Remember fraction squared is smaller than the original fraction. So here fraction cubed is smaller than fraction squared.

So the answer is (D).

Maybe she did what I did -- forgot that X had to be positive! In which case, X could be negative 1 and the answer would be A! Gotta read the statement carefully. I often screw up on that....