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On July 1st of the last year, the total number of employees

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by pre-gmat » Mon Oct 20, 2008 10:01 am
On July 1st of the last year, the total number of employees E were decreased by 10 percent. Without ay change in the salaries of the remaining employees, the arithmetic mean of the employee salary was 10 percent more after the decrease in number of employees than before the decrease. the total of the combines salaries of all the employees at company E after July 1st last year was what percentage of that before July 1st last year?

90%

99%

100%

101%

110%
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by vishubn » Mon Oct 20, 2008 10:23 am
My Take 99 %

as always its a percentage problem so i plugin values

before july 1st assume

number of E =100

and mean is 1000

that is 100,000/100=1000

so combined salary is 100,000

now after 1 st july

mean increased by 10 percent that is 1100 but 10 precent employess removed that is now 90 employesss

Sum=90*mean
Sum=99000

Question asks wat percnet was new combined salry than previeos

so it is 99%

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by vishubn » Mon Oct 20, 2008 10:26 am
wats the OA please ???

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by dmateer25 » Mon Oct 20, 2008 10:31 am
I worked the problem the exact same way as vishubn.

I also go with 99%
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by pre-gmat » Mon Oct 20, 2008 11:35 am
OA is 99%
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by pre-gmat » Mon Oct 20, 2008 11:40 am
what is you don't plug in numbers and do it algebraically?
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by pre-gmat » Mon Oct 20, 2008 11:46 am
got it Thanks!
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by cramya » Mon Oct 20, 2008 3:29 pm
If u dint plug in numbers

K-MEAN SALARY BEFORE JUL 1ST

x1+x2+.....xn / E = K

AFTER JULY 1ST

X1' + X2'+...XN' / .9E = 1.1K

We need to find X1' + X2'+...XN' / x1+x2+.....xn * 100

= 1.1K*.9E/KE*100 = 99%
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by pre-gmat » Mon Oct 20, 2008 5:58 pm
thanx
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