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On a certain assembly

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by figs » Mon May 25, 2009 4:22 am
On a certain assembly line, the rejection rate for Monday’s production was 4 per cent, for Tuesday’s 8 per cent, and for the two days combined 7 per cent. What was the ratio of Tuesday’s production to Monday’s production?

A. 3/1

B. 2/1

C. 1/1

D. 1/2

E. 1/3


oa..later
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by Giorgio » Mon May 25, 2009 5:27 am
Should be something like this:

0.04X+0.08Y=0.07
X+Y=1

Resolve and you get:
X=1/4 Y=3/4

Y=Thu
X=MO

so Y/X=3/1

answer:A
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Re: On a certain assembly

by dtweah » Mon May 25, 2009 5:36 am
figs wrote:On a certain assembly line, the rejection rate for Monday’s production was 4 per cent, for Tuesday’s 8 per cent, and for the two days combined 7 per cent. What was the ratio of Tuesday’s production to Monday’s production?

A. 3/1

B. 2/1

C. 1/1

D. 1/2

E. 1/3


oa..later
Let M and T be production. Then

96M/100 +92T/100 = 93(M+T)/100
3M=T
T/M =3/1
Choose A.
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