BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

★★★★★5.0559 reviews
GMATLiveTeach Starts Oct 17
Chris Peckover, Target Test Prep GMAT expert
LIVE ONLINE CLASSES

Get Ready for GMAT Test Day Faster with Live Online Classes

with Chris Peckover, 100th-Percentile GMAT Scorer

Oct 17 · Chris Peckover
Sat · 11:00 AM to 2:00 PM ET
Oct 20 · Chris Peckover
Tue, Thu · 8:00 to 10:00 PM ET
Oct 25 · Josh Braslow
Sun · 1:00 to 4:00 PM ET
Included
40 hours of live online classes + 6 months of TTP OnDemand
  • Attend the first class for free
  • Every class is recorded, so you never fall behind
View classes & enroll
Limited seats availableTarget Test Prep
EALiveTeachOnDemand 5 seats left Start anytime
EXECUTIVE ASSESSMENT

Target Test Prep EA OnDemand

Self-paced EA prep. Study on your schedule.

Logan Thompson
EXECUTIVE ASSESSMENT

Sep 6 to Dec 6, 2026

with Logan Thompson

165+ EA score guarantee
$05-day trial no automatic billing
Schedule
Sun · 9:30 AM to 12:30 PM ET
Included
40 hours of live online classes plus six months of access to the complete TTP EA OnDemand course.
  • 165+ EA Score Guarantee
  • 4,100+ Quant, Verbal, and Integrated Reasoning practice questions
  • 400+ hours of in-depth video lessons
  • 3,000+ step-by-step video solutions
View EA class & enroll Start free 5-day trial
Limited cohort · enrollment openTrial includes full course accessTarget Test Prep
GMATOnDemand Start anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

715+ score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions

Compare the format, schedule, and included access before enrolling. Prices and seat counts shown reflect the supplied offer details.

OG13 - Question 60 - confused

Expert replies
by topperdoggle » Sat Apr 27, 2013 5:09 am
Can someone give me some insight here? I read the answer explanation in the OG but it doesn't all follow. I don't see why the ratio amount of orangeade made and sold on the first day vs second day is 2:3. I know that on the first day it's 1:1 juice / water, and second day 1:2, but how do we know that they didn't make a million more glasses on the first day?

I guess I can't see the forest for the trees. Really appreciate someone straightening me out. :)
Join the discussion
Source: — Problem Solving |

by Anju@Gurome » Sat Apr 27, 2013 5:10 am
On a certain day, orangeade was made by mixing a certain amount of orange juice with an equal amount of water. On the next day, orangeade was made by mixing the same amout of orange juice with twice the amount of water. On both days, all the orangeade that was made was sold. If the revenue from selling the orangeade was the same for both days and if the orangeade was sold at $0.60 per glass on the first day, what was the price per glass on the second day?
a. .15
b. .2
c. .3
d. .4
e. .45
On the 1st day, 1 unit of orange juice was mixed with 1 unit of water.
So, total amount of orangeade = (1 + 1) = 2 units
If each glass contained n units of orangeade, total number of glasses sold = 2/n
As price per glass was $0.60, total revenue on the 1st day = (0.60)*(2/n)

On the 2nd day, 1 unit of orange juice was mixed with 2 units of water.
So, total amount of orangeade = (1 + 2) = 3 units
If each glass contained n units of orangeade, total number of glasses sold = 3/n
Total revenue on the 2nd day = Total revenue on the 1st day = (0.60)*(2/n)

Hence, price per glass on the 2nd day = (Total revenue)/(number of glasses sold) = (0.60)*(2/n)/(3/n) = (0.60)*(2/n)*(n/3) = (0.20)*2 = 0.40

The correct answer is D.
Last edited by Anju@Gurome on Sat Apr 27, 2013 5:44 am, edited 1 time in total.
Anju Agarwal
Quant Expert, Gurome

Backup Methods : General guide on plugging, estimation etc.
Wavy Curve Method : Solving complex inequalities in a matter of seconds.

§ GMAT with Gurome § Admissions with Gurome § Career Advising with Gurome §
Join the discussion

by faraz_jeddah » Sat Apr 27, 2013 5:22 am
Anju@Gurome wrote:

If each glass contained n units of orangeade, total number of glasses sold = 2/n
As price per glass was $0.60, total revenue on the 1st day = (0.60)*(2/n)

[/spoiler]
Can you give a deeper explanation on how you get 2/n?
Join the discussion

by Anju@Gurome » Sat Apr 27, 2013 5:42 am
faraz_jeddah wrote:Can you give a deeper explanation on how you get 2/n?
Let us assume on the 1st day, x liters of orange juice was mixed with x liters of water.
So, total amount of orangeade = (x + x) = 2x liters
If each glass contained n liters of orangeade, total number of glasses sold = 2x/n

For simplicity, I've assumed x = 1 as it doesn't matter how much juice was mixed with how much water as long as they are same. But if you are not convinced, we can proceed using with x in the same way.

As price per glass was $0.60, total revenue on the 1st day = $(0.60)*(2x/n)

On the 2nd day, x liters of orange juice was mixed with 2x liters of water.
So, total amount of orangeade = (x + 2x) = 3x liters
If each glass contained n liters of orangeade, total number of glasses sold = 3x/n
Total revenue on the 2nd day = Total revenue on the 1st day = (0.60)*(2x/n)

Hence, price per glass on the 2nd day = (Total revenue)/(number of glasses sold) = (0.60)*(2x/n)/(3x/n) = (0.60)*(2x/n)*(n/3x) = (0.20)*2 = 0.40

--------------------------------------------------------------------
In fact, if you understand the underlined part, then you'll see that we can assume n = 1 too. That means, on the first day 1 glass of juice was mixed with 1 glass of water to get 2 glasses of orangeade. So, total revenue on 1st day = $(0.60)*2 = $1.20

Now, on the second day 1 glass of juice was mixed with 2 glasses of water to get 3 glasses of orangeade. As the revenue on the 2nd day is also $1.20, the price per glass must be $1.20/3 = $0.40

Hope that helps.
Anju Agarwal
Quant Expert, Gurome

Backup Methods : General guide on plugging, estimation etc.
Wavy Curve Method : Solving complex inequalities in a matter of seconds.

§ GMAT with Gurome § Admissions with Gurome § Career Advising with Gurome §
Join the discussion

by GMATGuruNY » Sat Apr 27, 2013 7:03 am
On a certain day, orangeade was made by mixing a certain amount of of orange juice with an equal amount of water. On the next day, orangeade was made by mixing the same amount of orange juice with twice the amount of water. On both days, all the orangeade that was made was sold. If the revenue from selling the orangeade was the same for both days and if the orangeade was sold at $0.60 per glass on the first day, what was the price per glass on the second day?
A)$0.15 B)$0.20 C)$0.30 D)$0.40 E)$0.45
Let each glass = 1 unit.

First day:
Let water = 1 unit and juice = 1 unit.
Glasses = water + juice = 1+1 = 2.
Since each glass earns 60 cents, revenue = 2*60 = 120.

Second day:
Revenue = 120 (same as on the first day).
Since twice as much water is used, water = 2 units.
Juice = 1 unit (same as on the first day.)
Glasses = water + juice = 2+1 = 3.
Price per glass = revenue/glasses = 120/3 = 40.

The correct answer is D.
Private tutor exclusively for the GMAT and GRE, with over 20 years of experience.
Followed here and elsewhere by over 1900 test-takers.
I have worked with students based in the US, Australia, Taiwan, China, Tajikistan, Kuwait, Saudi Arabia -- a long list of countries.
My students have been admitted to HBS, CBS, Tuck, Yale, Stern, Fuqua -- a long list of top programs.

As a tutor, I don't simply teach you how I would approach problems.
I unlock the best way for YOU to solve problems.

For more information, please email me (Mitch Hunt) at [email protected].
Student Review #1
Student Review #2
Student Review #3
Join the discussion

by ygdrasil24 » Sat Apr 27, 2013 7:15 am
My Take:

Day 1: Juice = 1, Water =1,
Day 2: Juice = 1, Water =2
Assuming same profit% on sale(which we assume =0, for easy calculation)

A glass having half qty of juice is sold at 0.6
So, a glass having full qty of juice is sold at 1.2
So, a glass having 1/3 juice [ Day2 case] is sold at 0.4

Appreciate if it helped :lol: :lol:
Join the discussion

by fifafreak » Sun Apr 28, 2013 10:51 pm
day 1: O=100; W=100 => 200 units = 10 units/glass * 20 glasses =.60*20 = 12$
day 2: O=100; W=200 => 300 units = 10 units/glass * 30 glasses = 12 $ = 30*0.40 $ => 0.40$/glass
Join the discussion