OG12 PS #148

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jscpba: Junior | Next Rank: 30 Posts; Posts: 17; Joined: Wed Dec 08, 2010 8:45 pm

by jscpba » Sun Feb 06, 2011 9:20 am

What is the quickest way to solve this?

If x, y, and k are positive numbers such that (x/x+y)(10) + (y/x+y)(20)= k and if x is less than y, which of the following could be the value of k?

a. 10
b. 12
c. 15
d. 18
e. 30

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Source: Beat The GMAT — Problem Solving | Sun Feb 06, 2011 9:20 am

maihuna: Legendary Member; Posts: 1578; Joined: Sun Dec 28, 2008 1:49 amFollowed by: 9 members; Thanked: 82 times; GMAT Score:720

by maihuna » Sun Feb 06, 2011 9:59 am

it ca nbe viewed as weighted avg of 10 and 20, we knew the weighted avg will be close to 20 since x and y are positive no, and x < y, its kind of x/x+y will be less than y/x+y, so any answer more than 15 and less than 20 will satisfy. 18 is there.

Charged up again to beat the beast

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