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og ps 77

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by simba12123 » Mon Oct 20, 2008 5:51 am
if a square region has area x, what is the length of its diagonal in terms of x?

a. root x

b.root 2x

c.2 root x

d. x root 2

e. 2x

qa is b


however when plugging in numbers i cant see why d is wrong?
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by Neo2000 » Mon Oct 20, 2008 6:07 am
Let X = 25

The Side = 5
and Diagonal = 5Root2

However, the question says Diagonal in terms of the area so
D = Root(25*2) = Root 2X

P.s. i fell for the trap too :D
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Re: og ps 77

by sudhir3127 » Mon Oct 20, 2008 6:47 am
simba12123 wrote:if a square region has area x, what is the length of its diagonal in terms of x?

a. root x

b.root 2x

c.2 root x

d. x root 2

e. 2x

qa is b


however when plugging in numbers i cant see why d is wrong?
for me its more of a formula than anything else..

For a square..

Area = s^2 ( where "S" is the side ) and
diagonal is sqrt 2 * S

thus if the area is X . it means side is rt X
and diagonal is rt 2* rt X

which is

sqrt (2X)..

hence B .. hope that helps..
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by Scott@TargetTestPrep » Fri Jan 05, 2018 6:44 am
simba12123 wrote:if a square region has area x, what is the length of its diagonal in terms of x?

(A) √x
(B) √(2x)
(C) 2√x
(D) x√2
(E) 2x
We can create the following equation:

side^2 = x

side = √x

To calculate the diagonal of a square, multiply its side by √2.

So, the diagonal = (√x)(√2) = √(2x).

Answer: B

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