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OG: November 16, 2001, was a Friday. If each of the years 2004, 2008, and 2012 had 366 days,

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OG: November 16, 2001, was a Friday. If each of the years 2004, 2008, and 2012 had 366 days,

by AbeNeedsAnswers » Thu May 21, 2020 6:40 pm

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November 16, 2001, was a Friday. If each of the years 2004, 2008, and 2012 had 366 days, and the remaining years from 2001 through 2014 had 365 days, what day of the week was November 16, 2014?

A. Sunday
B. Monday
C. Tuesday
D. Wednesday
E. Thursday

A
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Re: OG: November 16, 2001, was a Friday. If each of the years 2004, 2008, and 2012 had 366 days,

by Jay@ManhattanReview » Fri May 22, 2020 6:24 am
AbeNeedsAnswers wrote: ↑
Thu May 21, 2020 6:40 pm
 November 16, 2001, was a Friday. If each of the years 2004, 2008, and 2012 had 366 days, and the remaining years from 2001 through 2014 had 365 days, what day of the week was November 16, 2014?

A. Sunday
B. Monday
C. Tuesday
D. Wednesday
E. Thursday

A
Given that information, we know that November 16, 2014 would fall after (10*365 + 3*366) days after November 16, 2001.

Since after every 7 days, the day repeats, we have to count the number of 7-days blocs in (10*365 + 3*366).

10*365 + 3*366 = 4,748 days

Number of 7-days blocs = Qutient of 4,748/7 = 678

Remainder of 4,748/7 = 4,748 – 678*7 = 2 days

Since 2 days is the reminder and November 16, 2001, was a Friday, November 16, 2014, would be a Friday + 2 = Sunday.

The correct answer: A

Hope this helps!

-Jay
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Re: OG: November 16, 2001, was a Friday. If each of the years 2004, 2008, and 2012 had 366 days,

by Scott@TargetTestPrep » Mon May 25, 2020 5:04 am
AbeNeedsAnswers wrote: ↑
Thu May 21, 2020 6:40 pm
 November 16, 2001, was a Friday. If each of the years 2004, 2008, and 2012 had 366 days, and the remaining years from 2001 through 2014 had 365 days, what day of the week was November 16, 2014?

A. Sunday
B. Monday
C. Tuesday
D. Wednesday
E. Thursday

A
We see that there is a 13-year span from November 16, 2001 to November 6, 2014. If each year were 365 days, the total number of days in this 13-year span would be 365 x 13 = 4,745 days. However, since 3 of the years during this span each has 1 extra day, the actual number of days in this span is 4,745 + 3 = 4,748 days. Since 4,748/7 = 678 R 2, we know that there were 678 weeks and 2 days from Friday, November 16, 2001 until November 16, 2014. The remainder of 2 tells us that November 16, 2014 was 2 days after Friday, so it was Sunday.

Answer: A

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Re: OG: November 16, 2001, was a Friday. If each of the years 2004, 2008, and 2012 had 366 days,

by GMATGuruNY » Mon Aug 17, 2020 10:42 am
AbeNeedsAnswers wrote: ↑
Thu May 21, 2020 6:40 pm
 November 16, 2001, was a Friday. If each of the years 2004, 2008, and 2012 had 366 days, and the remaining years from 2001 through 2014 had 365 days, what day of the week was November 16, 2014?

A. Sunday
B. Monday
C. Tuesday
D. Wednesday
E. Thursday
Between 2001 and 2014 are 10 non-leap years and 3 leap years.
Each non-leap year is composed of 365 days; each leap year is composed of 366 days.
Thus, from November 16, 2001 to November 16, 2014, the total number of days = 10(365) + 3(366).

Since November 16, 2001 is a Friday, every passing of 7 days will yield another Friday.
364 is a multiple of 7.
Rephrase the total number of days in terms of 364:
10(365) + 3(366) = 10(364+1) + 3(364+2) = 13(364) + 16 = 13(364) + 14 + 2 = (multiple of 7) + (multiple of 7) + 2 = Friday + 2 days = Sunday

The correct answer is A.
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