h = -16 (t - 3)^2 + 150.An object thrown directly upward is at a height of h feet after t seconds, where
h = -16 (t - 3)^2 + 150. At what height, in feet, is the object 2 seconds after it reaches its maximum height?
A)6
B)86
C)134
D)150
E)166
h = ("Negative number" * "Square of a number") + 150.
Maximum value of h is when the "Square of a number" is 0.
h = -16 (t - 3)^2 + 150.
h is maximum when t = 3 . For any t greater than or less than 3, the value of h is less than 150.
In conclusion, when t = 3 secs, the object is at the maximum height of 150 meters.
2 seconds after it reached the maximum height, t = 5
h = -16 (5 - 3)^2 + 150 feet.
h = (-16 * 4) + 150 feet.
h = -64 + 150 feet.
h = 86 feet.
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