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OG-12 DS #117

Expert replies
by papgust » Sat Mar 06, 2010 7:41 pm
In the figure above, points A, B, C, D, and E lie on a line. A is on both circles, B is the center of the smaller circle, C is the center of the larger circle, D is on the smaller circle, and E is on the larger circle. What is the area of the region inside the larger circle and outside the smaller circle?

(1) AB = 3 and BC = 2
(2) CD = 1 and DE = 4

Please refer the diagram in OG

OA: D


My doubt:

I actually selected A and ignored statement (ii) as insufficient because I thought that i should not trust the diagram without further information. In other words, statement (ii) says that CD=1 and DE=4. From the diagram, we could infer that CE is the radius and therefore CE = CD+DE = 1+4 = 5 (This is what is given in OG-12)

But, i thought that D could be outside the inner circle and could also be inside the inner circle. That is, there could be 2 possibilities

If D is outside the inner circle, then CE = CD+DE = 5 (radius of outer circle)
If D is inside the inner circle, then CE = DE - CD = 3 (radius of outer circle)

For this reason, i ignored B and selected A.

What is wrong in my thought? Did i go beyond the scope of ambiguity in diagrams? If so, why?
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Source: — Data Sufficiency |

by bpgen » Sun Mar 07, 2010 1:09 am
As it's saying 'D is on the smaller circle, and E is on the larger circle" , that means D, E are laying on circumference of circle... not inside or outside. Hope this helps.
"Ambition is the path to success. Persistence is the vehicle you arrive in."
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by papgust » Sun Mar 07, 2010 4:47 am
Alright. But, C could be either inside or outside the smaller circle. Is there any proof provided in the question stem that C is only inside the smaller circle?
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by bpgen » Sun Mar 07, 2010 6:53 am
What does it mean? If you see diagram it could be seen clearly... :-)

Anyway, would that position of C, affecting your decision making process?
Even for your sake, I could assume C is outside of small circle, still we could solve this problem..

(1) AB = 3 and BC = 2
(2) CD = 1 and DE = 4

so if C is inside, no issues, solution is in OG,
Let's see C is outside of small circle,
So, big circle's radius would be DE-CD, where small circle's diameter would be 2(DE-CD)-DE, i.e AD
Hope this helps.
"Ambition is the path to success. Persistence is the vehicle you arrive in."
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by papgust » Sun Mar 07, 2010 9:01 am
bpgen wrote:What does it mean? If you see diagram it could be seen clearly... :-)
My question is just this. It can be seen clearly from the diagram that C is inside the inner circle. Agreed. But the diagram is not measured to scale. Neither it is mentioned specifically that C falls within the inner circle.

So, to what extent i could trust the diagram?

Really appreciate you for being patient to answer my questions :)
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by kstv » Sun Mar 07, 2010 10:21 am
It is like the Emperors cloth , everyone can see it but I cannot see the diagram.
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by bpgen » Sun Mar 07, 2010 11:06 am
kstv, pls refer to OG-12 DS #117
"Ambition is the path to success. Persistence is the vehicle you arrive in."
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