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OG 11th edition Q 154- Have I oversimplified the problem?

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by Nidhs » Fri Jan 18, 2008 3:44 pm
In the following question, can someone please tell me if my reasoning is correct or if i have oversimplified the problem;

Is x negative?
(1) x^3(1-x^2)<0
(2) x^2-1<0

My answer is also c, as given the book...but my reasoning to it is the following;
acc to me st1 says- x^3<0 or (1-x^2)<0,
either x^3<0 could be true or (1-x^2)<0 could be true but not both as the value needs to be negative. As we don't know which one is true INSUFFICIENT

St2 x^2-1<0 but we don't know if x is positive or negative; so INSUFFICIENT

Combining 1 and 2 says that (1-x^2)is not less than 0. Hence, x^3<0 must be correct.

Do I have the right approach for solving this?
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Source: — Data Sufficiency |

by gabriel » Sat Jan 19, 2008 3:29 am
Seems right .. this is how I would have solved it

Regards
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by smar83 » Mon Jan 21, 2008 9:01 am
Nidhs,

Just an off topic question...

Which quant books are you referring to ? PR or Kaplan apart from OG.. ?

Which one sounds better to you ? I have PR math, planning to take Kaplan..

Appreciate your reply,

Thanks.
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by mollyrg » Thu Jan 24, 2008 11:24 am
Hi Smar83,

I think Kaplan will be good along with OG. PR is good to start off. But the level of maths is very easy.

Molly
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by smar83 » Thu Jan 24, 2008 11:35 am
mollyrg,


Thank you. Yes, I have exhausted PR.Planning to move over to kaplan pretty soon.

Thanks again.
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og 154 ds

by resilient » Sat Feb 09, 2008 6:28 pm
After througuhly testing numbers I do not understand how to even combine these to equations together. I do know that both 1 and 2 alone are insufficient but cant grasp the idea of them both together being sufficient. Help
Appetite for 700 and I scraped my plate!
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picking numbers

by resilient » Sat Feb 09, 2008 6:50 pm
by the way....the numbers I chose were..

statement 1. x=-2,-3

statement2. x= 1/2,-1/2
Appetite for 700 and I scraped my plate!
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Nidhs wrote:In the following question, can someone please tell me if my reasoning is correct or if i have oversimplified the problem;

Is x negative?
(1) x^3(1-x^2)<0
(2) x^2-1<0

My answer is also c, as given the book...but my reasoning to it is the following;
acc to me st1 says- x^3<0 or (1-x^2)<0,
either x^3<0 could be true or (1-x^2)<0 could be true but not both as the value needs to be negative. As we don't know which one is true INSUFFICIENT

St2 x^2-1<0 but we don't know if x is positive or negative; so INSUFFICIENT

Combining 1 and 2 says that (1-x^2)is not less than 0. Hence, x^3<0 must be correct.

Do I have the right approach for solving this?
Yeah I had the same issue, I split (1) x^3(1-x^2)<0 as X^3, (1-x), (1+x) though... that way it's either x<0 or x >0 and (1-x) <0 which is possible.

The method in the book is very lengthy and hopefully unnecessary?
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Nidhs wrote:In the following question, can someone please tell me if my reasoning is correct or if i have oversimplified the problem;

Is x negative?
(1) x^3(1-x^2)<0
(2) x^2-1<0

from one

the expression can be -ve if:

a) x is -ve given that /x/< 1 or
b) x +ve and /x/>1...........insuff

from 2

x^2 < 1 x can be +ve or -ve fraction. or 0........insuff

both

x is not 0 , /x/<1 and thus option (a) from one is valid...C
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og ds 154

by simba12123 » Fri Oct 24, 2008 9:16 am
I like the approach to this question. However, I am wondering how to combine these two statments. BOth statements yield positive and negative fractions. THerefore isnt it correct to say that the answer is E? IN order for c to be correct there must be common ground or agreement of shared values. I cant rationalize how this is c! please help clear this matter!
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