og 102

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resilient: Legendary Member; Posts: 789; Joined: Sun May 06, 2007 1:25 amFollowed by: 6 members; Location: Southern California, USA; Thanked: 15 times

by resilient » Sat May 24, 2008 5:06 pm

Is x/m(m^2+n^2+k^2)=xm+yn+zk?

1.z/k=x/m

2.x/m=y/n

Need this explained in steps. Want to break this down and simplify or rephrase somehow. Please do not just give answer or agreement that you agree with previous answer. Whats most beneficial for eveyone is different explanations.

Trying to figure out the most efficient way to tackle this.
c

Appetite for 700 and I scraped my plate!

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Source: Beat The GMAT — Data Sufficiency | Sat May 24, 2008 5:06 pm

aatech: Master | Next Rank: 500 Posts; Posts: 192; Joined: Tue Apr 29, 2008 7:41 am; Thanked: 14 times

by aatech » Sat May 24, 2008 5:16 pm

Can you please clarify x/m(m^2+n^2+k^2)

is [x*(m^2+n^2+k^2)]/m OR

x/[m*(m^2+n^2+k^2)]

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netigen: Legendary Member; Posts: 631; Joined: Mon Feb 18, 2008 11:57 pmFollowed by: 3 members; Thanked: 29 times

by netigen » Sat May 24, 2008 5:29 pm

Equation needs to be this - (x/m)(m^2+n^2+k^2)

C is the correct answer just plug the values to get it.

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resilient: Legendary Member; Posts: 789; Joined: Sun May 06, 2007 1:25 amFollowed by: 6 members; Location: Southern California, USA; Thanked: 15 times

og 102

by resilient » Sat May 24, 2008 7:11 pm

yes folks there is multiplication between the two

corrected stand as: (x/m)(m^2+n^2+k^2)

can we please break this one down to see what happened.

Appetite for 700 and I scraped my plate!

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aatech: Master | Next Rank: 500 Posts; Posts: 192; Joined: Tue Apr 29, 2008 7:41 am; Thanked: 14 times

by aatech » Sat May 24, 2008 7:34 pm

ANS C

(x/m)(m^2+n^2+k^2) - break this into 3 terms

First xm

Second x*n^2/m

Third x*k^2/m

Stmt 1 - z/k=x/m -- We can solve third term as k^2*z/k = zk

can't do anything about second term so NOT SUFF

Stmt 2 x/m=y/n -- We can solve second term as yn but can't do much about third term so NOT SUFF

Together, we find the answer as xm+yn+zk SUFF

Hope this clarifies your doubt

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