VJesus12 wrote:Of the integers between 100 and 799, inclusive, how many do not have digit 2 and 5?
(A) 310
(B) 320
(C) 410
(D) 420
(E) 520
Number of options for the hundreds digit = 5. (Of the seven digits 1-7, any but 2 or 5.)
Number of options for the tens digit = 8. (Of the ten digits 0-9, any but 2 or 5.)
Number of options for the units digit = 8. (Of the ten digits 0-9, any but 2 or 5.)
To combine these options, we multiply:
5*8*8 = 320.
The correct answer is
B.
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