# of Passengers

bhumika.k.shah wrote:The number of passengers on a certain bus at any given time is given by the equation P = –2(S – 4)2 + 32, where P is the number of passengers and S is the number of stops the bus has made since beginning its route. If the bus begins its route with no passengers, what is the value of S when the bus has its greatest number of passengers?

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MGMAT CAT

harshavardhanc wrote:

bhumika.k.shah wrote:The number of passengers on a certain bus at any given time is given by the equation P = –2(S – 4)2 + 32, where P is the number of passengers and S is the number of stops the bus has made since beginning its route. If the bus begins its route with no passengers, what is the value of S when the bus has its greatest number of passengers?

9
6
4
2
1

MGMAT CAT

you can view the equation as P=A+32

after the 4th stop, A is always -ve and hence, P will decrease.

before 4th stop, the value of (S-4) is least at S=1, and hence A in the above equation will be greatest. Remember S>0.

IMO, E. What's the OA?

bhumika.k.shah wrote:OA [spoiler]C=4[/spoiler]

harshavardhanc wrote:

bhumika.k.shah wrote:The number of passengers on a certain bus at any given time is given by the equation P = –2(S – 4)2 + 32, where P is the number of passengers and S is the number of stops the bus has made since beginning its route. If the bus begins its route with no passengers, what is the value of S when the bus has its greatest number of passengers?

9
6
4
2
1

MGMAT CAT

you can view the equation as P=A+32

after the 4th stop, A is always -ve and hence, P will decrease.

before 4th stop, the value of (S-4) is least at S=1, and hence A in the above equation will be greatest. Remember S>0.

IMO, E. What's the OA?

newton9 wrote:Can you please recheck the question..

IS is P = -2(S - 4)2 + 32 or P = -2(S - 4) ^ 2 + 32

If it is the second, then 4 will be the answer.

harshavardhanc wrote:

bhumika.k.shah wrote:OA [spoiler]C=4[/spoiler]

harshavardhanc wrote:

bhumika.k.shah wrote:The number of passengers on a certain bus at any given time is given by the equation P = –2(S – 4)2 + 32, where P is the number of passengers and S is the number of stops the bus has made since beginning its route. If the bus begins its route with no passengers, what is the value of S when the bus has its greatest number of passengers?

9
6
4
2
1

MGMAT CAT

you can view the equation as P=A+32

after the 4th stop, A is always -ve and hence, P will decrease.

before 4th stop, the value of (S-4) is least at S=1, and hence A in the above equation will be greatest. Remember S>0.

IMO, E. What's the OA?

please recheck the OA.

S=4 will give P=32.

S=1 will give P=44.

Or am I going wrong somewhere? any other takers?

el_torero wrote:the way i saw this this was noticed the term -2(s - 4)^2 is always negative, and only 0 when s = 4. which means the largest value of that term = 0 when s = 4. 32 is of course constant so the P(s) function achieves its maximum at s = 4.

just different wording than above, but through a different lens.