IMO:C

finance wrote:How many odd integers are there greater than integer X and less than integer Y??
1) There are 12 even integers between X & Y
2) There are 24 integers between X and Y?

Q: x < odd integers < y

1) We can't say that there are 12 odd integers because (1) we don't know what the END digits of this set are (2) we don't know whether this is a consecutive set or even the increment

2) Again same as above.

Together:
x < 24 integers < y
from (1) we know that there are 12 even, that must mean that there are 12 odd integers.

hence (c)

I thought exactly like you did, but unfortunately it is B:((

Choice 1), if there are 12 even integers, starting on an odd integer vs. starting on an even integer (i.e. the first number in the sequence is 1 vs. 2) impacts how many odd integers you will count. insufficient.

Using choice 2), we know there are 24 integers between x & y. automatically half of those integers must be odd. Regardless if the first integer is odd or even, you will pass 12 odd and 12 even integers. Sufficient.

Answer is B

Gurpinder wrote:

finance wrote:How many odd integers are there greater than integer X and less than integer Y??
1) There are 12 even integers between X & Y
2) There are 24 integers between X and Y?

Q: x < odd integers < y

1) We can't say that there are 12 odd integers because (1) we don't know what the END digits of this set are (2) we don't know whether this is a consecutive set or even the increment

2) Again same as above.

Together:
x < 24 integers < y
from (1) we know that there are 12 even, that must mean that there are 12 odd integers.

hence (c)

To see why the answer is B, let's go through the same question with a slight change:

How many odd integers are there greater than integer X and less than integer Y?
1) There are 2 even integers between X & Y
2) There are 4 integers between X and Y?

Statement 1
Could be X = 3, Y = 7 (4 and 6 in between) -> only 5 is in between
Could be X = 2, Y = 8 (4 and 6 in between) -> 3, 5, 7 all in between
[spoiler]Insuff.
[/spoiler]
Statement 2

Could be X = 3, Y = 8 (4-7 in between) -> 5, 7 in between
Could be X = 2, Y = 7 (3-6 in between) -> 3, 5 in between
[spoiler]This doesn't prove sufficiency, but it shows that in each case there are 2. More broadly, it is correct to say that half of the 4 integers must be odd, so we know it is 2.[/spoiler]