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O is the center of the semicircle. if angle BCO = 6√3...

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by AAPL » Fri Jan 12, 2018 3:10 pm
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O is the center of the semicircle. If anfle BCO = 6√3, What is the area of triangle ABO?

$$A.\ 4\sqrt{3}$$
$$B.\ 6\sqrt{3}$$
$$C.\ 9\sqrt{3}$$
$$D.\ 12\sqrt{3}$$
$$E.\ 24\sqrt{3}$$

The OA is C.

Is there a strategic approach to this PS question? Can any experts help me? Please. Thanks!
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by Brent@GMATPrepNow » Sat Jan 13, 2018 6:11 am
AAPL wrote:Image

O is the center of the semicircle. If anfle BCO = 6√3, What is the area of triangle ABO?

$$A.\ 4\sqrt{3}$$
$$B.\ 6\sqrt{3}$$
$$C.\ 9\sqrt{3}$$
$$D.\ 12\sqrt{3}$$
$$E.\ 24\sqrt{3}$$

The OA is C.

Is there a strategic approach to this PS question? Can any experts help me? Please. Thanks!
I don't think you correctly transcribed the question.
If we're not given any lengths at all, it's impossible to find the area of triangle ABO

Cheers,
Brent
Brent Hanneson - Creator of GMATPrepNow.com
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by AAPL » Sat Jan 13, 2018 1:01 pm
Oh! I so sorry! I have a mistake!
The question say,

O is the center of semicirle. If angle BCO = 30 and BC = 6√3, what is the area of triangle ABO?

Thank you so much!
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