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by thephoenix » Sun Apr 11, 2010 5:26 am
imo b
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by magizhan » Sun Apr 11, 2010 5:49 am
Isn't the answer E?

As the square makes the number smaller in case of proper fractions all 3 are valid options.

I could clearly be true.

If x,y and z are 1/4, 1/3, 2/3 respectively II could be true

If x,y and z are 2/3, 1/3, 1/2 respectively III could be true.

Hence E.
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by pops » Sun Apr 11, 2010 6:25 am
neerajkumar1_1 wrote:need the solution
Ans should be E
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by outreach » Sun Apr 11, 2010 7:52 am
x > y^2 > z^4, all the terms would be positive (since we have even powers of y & z).

x can be any +ve number (may be fraction as well) and y & z have to be necessarily fractions. Hence, I holds true.

For II. Consider, x=1/4, y=1/3, z=1/2. This satisfies given inequality. Hence, II also holds true.

For III. Consider x=1, y=1/3,z=1/2. This satisfies given inequality. Hence, III also holds true.

Hence, E.
neerajkumar1_1 wrote:need the solution
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