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by sukhman » Sat Oct 12, 2013 6:55 am
Find the number of consecutive zeros at the end of the following numbers.


1!*2!*3!*4*5------50!

a.235 b.12 c.262 d.105
Last edited by sukhman on Sat Oct 12, 2013 8:10 am, edited 1 time in total.
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by theCodeToGMAT » Sat Oct 12, 2013 7:23 am
Sukhman, this is a GMAT FORUM and NOT CAT FORUM.

Also, avoid including two or more questions in the same POST; it creates confusion.


For Q1. Is the Answer [spoiler]{C} [/spoiler]
1-4 --> 0x5
5-9 --> 1x5
10-14 --> 2x5
15-19 --> 3x5
20-24 --> 4x5
25-29 --> (5+1)x5
30-34 --> (6+1)x5
35-39 --> (7+1)x5
40-44 --> (8+1)x5
45-49 --> (9+1)x5
50 ---> 10 + 2

Sum = 262
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