Find the maximum value of n such that 570*60*30*90*100*700*343*720*81 is perfectly divisible by 30^n
A. 12 B.11 C.14 D. 13
A. 12 B.11 C.14 D. 13
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Ideally, it should be done by considering for 2,3 and 5 and then consider the lowest power. However, we can see that "5" & "2" are present in almost all of the numbers.. So, the possibility of occurrence of "3" seems minimal; that's why I considered "3"sukhman wrote:can you plz make it clear why is not divided by 5 since 30=2*3*5 Though your answer is correct
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