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Number system

Expert replies
by goyalsau » Mon Nov 15, 2010 2:42 am
HI! Friends,

Yesterday one of my friend asked one question. It is from Number Properties. Please share your views


One number is {159 * 66 * 99 * 135 * 29 * 34 } What we should subtract from the number to make it divisible by 31 ?

I don't remember the options exactly,

they were like

11
9
3
4

Or may be i am not posting the right options. but i just want to know how to approach these kind of questions. I am completely confused.............
Saurabh Goyal
[email protected]
-------------------------


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Source: — Problem Solving |

by Rahul@gurome » Mon Nov 15, 2010 3:40 am
goyalsau wrote:HI! Friends,

Yesterday one of my friend asked one question. It is from Number Properties. Please share your views


One number is {159 * 66 * 99 * 135 * 29 * 34 } What we should subtract from the number to make it divisible by 31 ?

I don't remember the options exactly,

they were like

11
9
3
4

Or may be i am not posting the right options. but i just want to know how to approach these kind of questions. I am completely confused.............
We have to use modular arithmetic here. According to modular arithmetic, (a mod b) = c means when a is divided by b, the remainder is c. A fundamental formula in modular arithmetic is
  • (ab) mod c = [a mod c * b mod c] mod c
Say, N = 159*66*99*135*29*34
Therefore, (N mod 31) = [{(159 mod 31)*(66 mod 31)*(99 mod 31)*(135 mod 31)*(29 mod 31)*(34 mod 31)} mod 31]

Now,
  • 159 mod 31 = 4
    66 mod 31 = 4
    99 mod 31 = 6
    135 mod 31 = 11
    29 mod 31 = 29
    34 mod 31 = 3
Thus, (N mod 31)
= [{4*4*6*11*29*3} mod 31]
= [{32*99*29} mod 31]
= [{(32 mod 31)*(99 mod 31)*(29 mod 31)} mod 31]
= [{1*6*29} mod 31]
= 174 mod 31
= 19

Therefore we must subtract 19 from N to make it divisible by 31.
Rahul Lakhani
Quant Expert
Gurome, Inc.
https://www.GuroMe.com
On MBA sabbatical (at ISB) for 2011-12 - will stay active as time permits
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by beat_gmat_09 » Mon Nov 15, 2010 4:19 am
Is this a GMAT question ? Source ?
Hope is the dream of a man awake
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by goyalsau » Mon Nov 15, 2010 4:44 am
beat_gmat_09 wrote:Is this a GMAT question ? Source ?
I don't know buddy one of my friend asked me this question...

Rahul has provided a splendid solution, But the thing is { its very hard to remember formula } approach is good but i don't know will i able to remember it when i will be asked the same question again..........
Saurabh Goyal
[email protected]
-------------------------


EveryBody Wants to Win But Nobody wants to prepare for Win.
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by goyalsau » Mon Nov 15, 2010 5:16 am
Rahul thanks for the Wonderfull Solution.

can we use this property to solve one more question.

76 ^ 47 is the number and we have to make it divisible by 47

29 ^ 47 mode 47

it can we written as 841 ^ 23 * 29 { 47 * 17 = 799 }

42 ^ 23 * 29 mode 47

1764 ^ 11 * 29 * 42 mode 47

25 ^ 11 * 29 * 42 mode 47

525 ^5 * 29 * 25 * 42 mode 47

8 ^ 5 * 29 * 25 * 42 mode 47

64 ^ 2 * 8 * 29 * 25 * 42 mode 47

27 ^ 2 * 8 * 29 * 25 * 42 mode 47

729 * 8 * 29 * 25 * 42 mode 47

24 * 8 * 29 * 25 * 42 mode 47

192 * 725 * 42 mode 47

4 * 20 * 42 mode 47

80 * 42 mode 47

33 * 42 mode 47

462 * 3 mode 47

39 * 3 mode 47

117 mode 47

23 mode 47

we need to subtract 23 from 76 ^ 47
Saurabh Goyal
[email protected]
-------------------------


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