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by ashhchdg » Mon Aug 15, 2011 6:19 am
How many terms are there in the set of consecutive integers from -18 to 33, inclusive ?

I have a doubt in this...should we consider 0 too while counting the consecutive integers ?
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by kmittal82 » Mon Aug 15, 2011 6:21 am
Yes, 0 is an integer
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by Aman verma » Mon Aug 15, 2011 9:29 am
You mentioned
How many terms
, so we should first of all consider what is the difference between each term i.e whether it is a set of consecutive integers or consecutive odd integers or consecutive even integers or consecutive integers with larger/smaller differences. Next you mention
in the set of consecutive integers
, so we should know the difference between each term is one. So if we move on from -18 with increments of 1 towards 33, we should generally consider 0 as part of the set. So IMO: 0 should be considered while counting the given set of consecutive integers. Also I would like to know if anyone has any other views on this one.
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by edvhou812 » Mon Aug 15, 2011 9:03 pm
Don't even think about the zero. Just use the formula to calculate the number of terms in a set: (x-y)+1

33-(-18)+1=33+18+1=52
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by GmatKiss » Mon Aug 15, 2011 10:29 pm
+1 with Kmittal,

0 should be considered as a digit and the no.of terms from -18 to 33 should be 52
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