140*n = (2^2)*5*7*nsud21 wrote:If 140*n is the square of an integer, where n is an integer. What is the least value of n?
Now if 140*n is a square of an integer, then all the factors of 140*n must appear in it even number of times. There are two 2's already in 140*n. Hence, n must contain 5 and 7 in it.
Hence, minimum possible value of n = 5*7 = 35
