BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

★★★★★5.0559 reviews
GMATLiveTeach 7 seats left
Chris Peckover
NEXT LIVE COHORT

Oct 13 to Jan 7, 2027

with Chris Peckover

Schedule
Tue, Thu · 8:00 to 10:00 PM ET
Included
40 live hours + 6 months of GMAT OnDemand
  • Live instruction and real-time questions
  • Class recordings and assigned practice
View class & enroll
Limited cohort · enrollment openTarget Test Prep
EALiveTeach 5 seats left
Logan Thompson
EXECUTIVE ASSESSMENT

Sep 6 to Dec 6, 2026

with Logan Thompson

Schedule
Sun · 9:30 AM to 12:30 PM ET
Included
Live EA class + 6 months of EA OnDemand
  • Expert-led weekly online sessions
  • EA Masterclass access between classes
View EA class & enroll
Limited cohort · enrollment openTarget Test Prep
GMATOnDemand Start anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

130-point score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions
Start free 5-day trial
Read 559 reviewsTarget Test Prep

Compare the format, schedule, and included access before enrolling. Prices and seat counts shown reflect the supplied offer details.

Number Properties - multiples of 5 (gmat prep)

Expert replies
Post new topic Post Reply
Previous Topic Next Topic
Senior | Next Rank: 100 Posts
Posts: 42
Joined: Tue Jun 17, 2008 1:18 pm
Thanked: 2 times
by kshin78 » Sat Aug 09, 2008 1:13 pm
If n is a multiple of 5 and n = p^2q where p & q are prime numbers, which of the following must be a multiple of 25?

a. p^2
b. q^2
c. pq
d. p^2q^2
e. p^3q

Please provide an explanation. Thanks in advance!!
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Source: — Problem Solving |
Legendary Member
Posts: 1153
Joined: Wed Jun 20, 2007 6:21 amFollowed by: 2 members
Thanked: 146 times

by parallel_chase » Sat Aug 09, 2008 2:13 pm
n=p^2q

we know that n is a multiple of 5.
p and q are different prime numbers and one of them has to be 5, then only we can be assured that n is a multiple of 5.

25=5*5

Therefore, p^2q^2 will ensure that we have two 5's i.e. multiple of 25, irrespective of whether p is 5 or q is 5.

Hence D is the answer.
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Junior | Next Rank: 30 Posts
Posts: 25
Joined: Sat Aug 04, 2007 5:17 am
Location: Dallas

by drizzle » Sun Aug 10, 2008 7:16 am
parallel_chase wrote:n=p^2q

we know that n is a multiple of 5.
p and q are different prime numbers and one of them has to be 5, then only we can be assured that n is a multiple of 5.

Hence D is the answer.
here p should be 5 right...or else n can't be mulitple of 5...hope i'm not missing anything...
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Legendary Member
Posts: 1153
Joined: Wed Jun 20, 2007 6:21 amFollowed by: 2 members
Thanked: 146 times

by parallel_chase » Sun Aug 10, 2008 8:40 am
drizzle wrote:
parallel_chase wrote:n=p^2q

we know that n is a multiple of 5.
p and q are different prime numbers and one of them has to be 5, then only we can be assured that n is a multiple of 5.

Hence D is the answer.
here p should be 5 right...or else n can't be mulitple of 5...hope i'm not missing anything...
q can also be 5. If q is 5 n would still be a multiple of 5
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Legendary Member
Posts: 661
Joined: Tue Jul 08, 2008 12:58 pm
Location: France
Thanked: 48 times

by pepeprepa » Sun Aug 10, 2008 8:41 am
Agree with D)
p^2q^2 is p^2 * q^2
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Senior | Next Rank: 100 Posts
Posts: 42
Joined: Tue Jun 17, 2008 1:18 pm
Thanked: 2 times

by kshin78 » Sun Aug 10, 2008 12:27 pm
parallel_chase wrote:n=p^2q

we know that n is a multiple of 5.
p and q are different prime numbers and one of them has to be 5, then only we can be assured that n is a multiple of 5.

25=5*5

Therefore, p^2q^2 will ensure that we have two 5's i.e. multiple of 25, irrespective of whether p is 5 or q is 5.

Hence D is the answer.
Thanks! I should have realized p or q had to be 5....
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Newbie | Next Rank: 10 Posts
Posts: 1
Joined: Wed Jan 07, 2009 8:06 am

by ritubahl » Tue Apr 07, 2009 10:08 am
I am sorry I still don't get it - how can n be a multiple of 5 if p is not a multiple of 5?
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Master | Next Rank: 500 Posts
Posts: 107
Joined: Wed Mar 04, 2009 4:39 am
Location: Vancouver
Thanked: 9 times
GMAT Score:750

by pakaskwa » Tue Apr 07, 2009 12:56 pm
The original question was not clear:
n=p^2q

Is it n=(p^2)*q, or n=p^(2q)?
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Legendary Member
Posts: 1169
Joined: Sun Jul 06, 2008 2:34 amFollowed by: 1 member
Thanked: 25 times

by aj5105 » Mon May 04, 2009 2:09 am
n=(p^2)*q
pakaskwa wrote:The original question was not clear:
n=p^2q

Is it n=(p^2)*q, or n=p^(2q)?
Top
Join the discussion
Log in to postLogin with Googleuse password
QUOTE IN REPLY
Post new topic Post Reply
• Page 1 of 1