BREAKING: Target Test Prep releases Brand New 2026 On Demand GMAT prep course

Redeem

Target Test Prep · GMAT

Choose how you want to prepare

Learn live with an expert or move at your own pace. Every option includes the complete TTP study system.

★★★★★5.0559 reviews
GMATLiveTeach Starts Oct 17
Chris Peckover, Target Test Prep GMAT expert
LIVE ONLINE CLASSES

Get Ready for GMAT Test Day Faster with Live Online Classes

with Chris Peckover, 100th-Percentile GMAT Scorer

Oct 17 · Chris Peckover
Sat · 11:00 AM to 2:00 PM ET
Oct 20 · Chris Peckover
Tue, Thu · 8:00 to 10:00 PM ET
Oct 25 · Josh Braslow
Sun · 1:00 to 4:00 PM ET
Included
40 hours of live online classes + 6 months of TTP OnDemand
  • Attend the first class for free
  • Every class is recorded, so you never fall behind
View classes & enroll
Limited seats availableTarget Test Prep
EALiveTeachOnDemand 5 seats left Start anytime
EXECUTIVE ASSESSMENT

Target Test Prep EA OnDemand

Self-paced EA prep. Study on your schedule.

Logan Thompson
EXECUTIVE ASSESSMENT

Sep 6 to Dec 6, 2026

with Logan Thompson

165+ EA score guarantee
$05-day trial no automatic billing
Schedule
Sun · 9:30 AM to 12:30 PM ET
Included
40 hours of live online classes plus six months of access to the complete TTP EA OnDemand course.
  • 165+ EA Score Guarantee
  • 4,100+ Quant, Verbal, and Integrated Reasoning practice questions
  • 400+ hours of in-depth video lessons
  • 3,000+ step-by-step video solutions
View EA class & enroll Start free 5-day trial
Limited cohort · enrollment openTrial includes full course accessTarget Test Prep
GMATOnDemand Start anytime
SELF-PACED MASTERCLASS

Target Test Prep GMAT OnDemand

Complete access from day one. Study on your schedule.

715+ score guarantee
$0to start then $127/mo
  • Personalized study plan and analytics
  • Thousands of lessons and practice questions

Compare the format, schedule, and included access before enrolling. Prices and seat counts shown reflect the supplied offer details.

Number Comparison Problem

Expert replies
by vongdn » Tue Oct 05, 2010 9:03 pm
If N and P are integers, is P > 0 ?

(1) N + 1 > 0
(2) NP > 0


I see that (1) is insufficient.

Wouldn't (2) be sufficient though? Cause you would divide both sides of the statement by N and P > 0 right? Or is that wrong?

The answer is that Both together is sufficient, but I don't see it.
Join the discussion
Source: — Data Sufficiency |

by shovan85 » Tue Oct 05, 2010 10:12 pm
(2) will not be sufficient.

Because NP > 0 then you cannot divide both sides with N.

We know +ve * +ve = +ve and _ve * -ve = -ve.

If NP > 0 then either N and P both greater than zero or both less than zero.

However if you combine both then you are sure N > 1 from (1) so N is +ve. Hence P must be +ve.

IMO C
Join the discussion

by neerajkumar1_1 » Tue Oct 05, 2010 10:16 pm
question is asking whether P is +ve or P>0

statement 1) N +1 > 0
nothing abt P, this insufficient

statement 2) NP > 0

when product of 2 integers is +ve, this means that either both are positive or both are negative
since P can be both +ve and -ve, statement 2 is insufficient.

together,
N > -1
and NP >0
since N is an integer N >=0

since the product NP>0
hence N will be +ve,
since N is +ve, P will have to be +ve
Hence, sufficient.

IMO: C

to answer your question, u should be careful when dividing both side by N with inequalities... since u dont know whether N is +ve or -ve

Ur calculation is fine, but u r assuming N is +ve...
but u should consider both..
so in this case...
if N is +ve
P > 0 or +ve
but if N is -ve
P<0 or -ve

I would suggest that you revise ur inequalities a bit more...

Hope this helps!!!
Join the discussion

by shovan85 » Tue Oct 05, 2010 10:45 pm
shovan85 wrote:
However if you combine both then you are sure N > 1 from (1) so N is +ve. Hence P must be +ve.

IMO C
Sorry I made a mistake....N>-1 :)
Join the discussion

by blaster » Wed Oct 06, 2010 1:22 am
i think , key point here is N>-1 , so N is positive (statement 1) .
Join the discussion

by shovan85 » Wed Oct 06, 2010 4:54 am
blaster wrote:i think , key point here is N>-1 , so N is positive (statement 1) .
N > -1 does not necessarily makes N is +ve. It can be negative fractions or zero.
As NP>0 we cannot take n=0.
Join the discussion

by Yanat » Wed Oct 06, 2010 7:42 am
IMO the answer is C.
Join the discussion