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by gmatmachoman » Thu Jun 17, 2010 12:32 am
The price of Darjeeling tea (in rupees per kilogram) is 100 + 0.10n, on the nth day of 2007 (n = 1, 2, ......, 100), and then
remains constant. On the other hand, the price of Ooty tea (in rupees per kilogram) is 89 + 0.15n, on the nth day of 2007
(n = 1, 2, ......., 365). On which date in 2007 will the prices of these two varieties of tea be equal?


(1) April 11 (2) May 20 (3) April 10 (4) June 30 (5) May 21
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Source: — Problem Solving |

by kvcpk » Thu Jun 17, 2010 12:46 am
Answer is May 20.

What is OA?
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by amising6 » Thu Jun 17, 2010 12:49 am
on 100 th day price of darjeeling tea =100+0.10*100=110
so now need to find the day when value of ooty tea will be 110
so we can equate 89 + 0.15n=110
so we will get n=140 on solving
so starting from 1st jan 140 th day will be may 20 as feb has 28 days(2007 is not a leap year)

good problem already it has come in one of the entarnce exam
Ideation without execution is delusion
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