How many triangles can be drawn with 17 points, if 5, 7 and 8 of them are in three different lines? The three lines intersect each other in pairs.
1. 680
2. 136
3. 569
4. 171
1. 680
2. 136
3. 569
4. 171
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srcc25anu wrote:How many triangles can be drawn with 17 points, if 5, 7 and 8 of them are in three different lines? The three lines intersect each other in pairs.
1. 680
2. 136
3. 569
4. 171
Number of 3 point combinations = 17C3 = 680srcc25anu wrote:How many triangles can be drawn with 17 points, if 5, 7 and 8 of them are in three different lines? The three lines intersect each other in pairs.
1. 680
2. 136
3. 569
4. 171
stormier wrote:Number of 3 point combinations = 17C3 = 680srcc25anu wrote:How many triangles can be drawn with 17 points, if 5, 7 and 8 of them are in three different lines? The three lines intersect each other in pairs.
1. 680
2. 136
3. 569
4. 171
Of these there are several 3-point combinations that lie on a straight line and do not form a triangle, so we need to discount them.
Number of 3 point combinations that lie on a straight line = 8C3 + 5C3 + 7C3 = 101
Thus number of unique triangles = 680 - 101 = 579
This is a really tough problem. What's the OA ?