No. Of Sweaters Sold

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chetanojha: Master | Next Rank: 500 Posts; Posts: 125; Joined: Sun Sep 16, 2007 1:38 pm; Thanked: 6 times

by chetanojha » Mon Aug 31, 2009 3:51 am

Last Friday a certain shop sold 3/4 of the sweaters in its inventory. Each sweater sold or $20. What was the total revenue last Friday from the sale of these sweaters?

(1) When the shop opened last Friday, there were 160 sweaters in its inventory.
(2) All but 40 sweaters in the shop’s inventory were sold last Friday.

OA: D

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Source: Beat The GMAT — Data Sufficiency | Mon Aug 31, 2009 3:51 am

glorydefined: Senior | Next Rank: 100 Posts; Posts: 43; Joined: Tue Mar 31, 2009 9:54 am; Thanked: 2 times

by glorydefined » Mon Aug 31, 2009 4:45 am

Yes indeed 'D' is the correct answer.

Option (1)- It gives the total number of sweaters that were in the inventory on friday, which is 160. So 3/4 of 160 = 120 and the revenue is 120*20= 2400$.

Option (2)- It says "ALL" but 40 sweaters in the shop's inventory were sold last friday. So assume if you have x number of sweaters in the inventory. Then combining the question and the option 2, we get (3/4)*x=x-40, and solving for x gives x=160. And when you know the total number of sweaters in the inventory (3/4)*160 is 120 and 120*20=2400$.

Hence the option D.

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chetanojha: Master | Next Rank: 500 Posts; Posts: 125; Joined: Sun Sep 16, 2007 1:38 pm; Thanked: 6 times

by chetanojha » Mon Aug 31, 2009 5:11 am

glorydefined wrote:Yes indeed 'D' is the correct answer.

Option (1)- It gives the total number of sweaters that were in the inventory on friday, which is 160. So 3/4 of 160 = 120 and the revenue is 120*20= 2400$.

Option (2)- It says "ALL" but 40 sweaters in the shop's inventory were sold last friday. So assume if you have x number of sweaters in the inventory. Then combining the question and the option 2, we get (3/4)*x=x-40, and solving for x gives x=160. And when you know the total number of sweaters in the inventory (3/4)*160 is 120 and 120*20=2400$.

Hence the option D.

Thank. Got it.

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