25 men reap a field in 20 days . when should 15 men leave the work.if the whole field is to be reaped in 37-1/2 days after they leave the work? a.5 b.7 c.15 d.24 e.none Oa to follow From : Gmatclub. forum

Answer is A- 5 days. Let the work be 2000 completed units: 25 men take 20 days for 2000 units, So 1 man can complete 2000/25 = 80 units in 20 days. So 1 man can complete 80/20 = 4 units in 1 day______________(1) 15 people leave the job after some days, After they leave the time taken is 37-1/2 days. Therefore it took 10 people to complet X units in 37.5 days. 10 men can complete 4*10 = 40 units in 1 day_________from (1) Therefore X = 37.5 * 40 = 1500 units of work. The remainin 500 units (2000- 1500) was completed by 25 men before 15 men left the job. Therefore, 25 men took 500 / 4*25 = 5 days to complete 500 units of work. Therefore , answer is A.

It could also be done as follows: Let us assume that the 15 men leave after x days, Therefore, total men days---> 25 * 20 = 25 * x + 10 * 37 1/2 [10 because 15 men leave) Upon solving the equation we get, x = 5 days Hence OA = A. Thanks.

Ozlemg wrote:25 men reap a field in 20 days . when should 15 men leave the work.if the whole field is to be reaped in 37-1/2 days after they leave the work? a.5 b.7 c.15 d.24 e.none Oa to follow From : Gmatclub. forum I posted a solution here: https://www.beatthegmat.com/25-men-reap- ... 40494.html